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2 years ago

12

There is more to come CLICK HEREEEEEEEEE

2 answers:

GaryK [48]2 years ago

7 0

Answer:

A

Step-by-step explanation:

1/4 + 1/4 + 1/4 + 1/4 + 1/4 = 1/4 * 5

A represents 1/4 * 5

B represents 1/4 * 3

C represents 2/3 * 4

D represents 3/5 *7

Hope this helps :)

dlinn [17]2 years ago

5 0

Step-by-step explanation:

1/4+1/4+1/4+1/4+1/4

cancel B because it is 1/4+1/4+1/4

cancel C because it is 1/3+1/3+1/3+1/3

cancel D because it is 3/5+3/5+3/5+3/5+3/5+3/5+3/5

the right option is a because it is A because that is 1/4+1/4+1/4+1/4+1/4

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Solve x2-8x=3 by completing the square. which is the solution set of the equation

Mazyrski [523]

we have

$x^{2}-8x=3$

Complete the square. Remember to balance the equation by adding the same constants to each side

$x^{2}-8x+16=3+16$

$x^{2}-8x+16=19$

Rewrite as perfect squares

$(x-4)^{2}=19$

$(x-4)^{2}=19\\ (x-4)=(+/-)\sqrt{19} \\ \\ x1=4+\sqrt{19} =8.359\\ x2=4-\sqrt{19} =-0.359$

therefore

the answer is

$x1=4+\sqrt{19} =8.359\\x2=4-\sqrt{19} =-0.359$

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3 years ago

Read 2 more answers

Write in point slope form an equation of the line that passes through the given point and has the given slope: (0,1); m= 2

sergey [27]

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$\diamond\large\blue\textsf{\textbf{\underline{\underline{Question:-}}}}\diamond$

Write an equation for the line that passes through (0, 1) and has a slope of 2 (in point-slope form).

$\diamond\large\blue\textsf{\textbf{\underline{\underline{Answer and How to Solve:-}}}}\diamond$

<u>Point-slope form</u>:-

$\sf{y-y_1=m(x-x_1)}$

Substitute 1 for y₁, 2 for m, and 0 for x₁:-

$\sf{y-1=2(x-0)}$

So we conclude that Option B is correct.

<h3>Good luck.</h3>

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2 years ago

I WILL GIVE BRAINLIEST!!!

hram777 [196]

Answer:

Step-by-step explanation:

6 0

3 years ago

Find the work done by F= (x^2+y)i + (y^2+x)j +(ze^z)k over the following path from (4,0,0) to (4,0,4)

babunello [35]

$\vec F(x,y,z)=(x^2+y)\,\vec\imath+(y^2+x)\,\vec\jmath+ze^z\,\vec k$

We want to find $f(x,y,z)$ such that $\nabla f=\vec F$ . This means

$\dfrac{\partial f}{\partial x}=x^2+y$

$\dfrac{\partial f}{\partial y}=y^2+x$

$\dfrac{\partial f}{\partial z}=ze^z$

Integrating both sides of the latter equation with respect to $z$ tells us

$f(x,y,z)=e^z(z-1)+g(x,y)$

and differentiating with respect to $x$ gives

$x^2+y=\dfrac{\partial g}{\partial x}$

Integrating both sides with respect to $x$ gives

$g(x,y)=\dfrac{x^3}3+xy+h(y)$

Then

$f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+h(y)$

and differentiating both sides with respect to $y$ gives

$y^2+x=x+\dfrac{\mathrm dh}{\mathrm dy}\implies\dfrac{\mathrm dh}{\mathrm dy}=y^2\implies h(y)=\dfrac{y^3}3+C$

So the scalar potential function is

$\boxed{f(x,y,z)=e^z(z-1)+\dfrac{x^3}3+xy+\dfrac{y^3}3+C}$

By the fundamental theorem of calculus, the work done by $\vec F$ along any path depends only on the endpoints of that path. In particular, the work done over the line segment (call it $L$ ) in part (a) is

$\displaystyle\int_L\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(4,0,0)=\boxed{1+3e^4}$

and $\vec F$ does the same amount of work over both of the other paths.

In part (b), I don't know what is meant by "df/dt for F"...

In part (c), you're asked to find the work over the 2 parts (call them $L_1$ and $L_2$ ) of the given path. Using the fundamental theorem makes this trivial:

$\displaystyle\int_{L_1}\vec F\cdot\mathrm d\vec r=f(0,0,0)-f(4,0,0)=-\frac{64}3$

$\displaystyle\int_{L_2}\vec F\cdot\mathrm d\vec r=f(4,0,4)-f(0,0,0)=\frac{67}3+3e^4$

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3 years ago

Find the ordered pair for the equation: y = 2x + 10 where x = 3

pogonyaev

IT IS 15 BECAUSE YOU HAVE TO ADD IT UP

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4 years ago

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