Which of the following is NOT a solution to the graph?

Mathematics

1 answer:

Luden [163]4 years ago

7 0

Answer:

5 1/4 times 1/2 = 2.625. as a fraction 2.625 is 2 5/8 because .625 could be drawn out to 625/1000 125 goes into 625 and 1,000 625 divided by 125 = 5 and 1,000 divided by 125 is 8 we already had 2 so 2 5/8

Step-by-step explanation:

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Any one that knows this please help thanks!

rjkz [21]

The answer is -7/8 the alternative answer is 0.875

6 0

3 years ago

Let R be the region in the first quadrant bounded by the graphs of y =x^2 and y=2x, as shown in the figure above. The region R i

Kobotan [32]

Answer:

The area between the two functions is approximately 1.333 units.

Step-by-step explanation:

If I understand your question correctly, you're looking for the area surrounded by the the line y = 2x and the parabola y = x², (as shown in the attached image).

To do this, we just need to take the integral of y = x², and subtract that from the area under y = 2x, within that range.

First we need to find where they intersect:

2x = x²

2 = x

So they intersect at (2, 4) and (0, 0)

Now we simply need to take the integrals of each, subtracting the parabola from the line (as the parabola will have lower values in that range):

$a = \int\limits^2_0 {2x} \, dx - \int\limits^2_0 {x^2} \, dx\\\\a = x^2\left \{ {{x=2} \atop {x=0}} \right - \frac{x^3}{3}\left \{ {{x=2} \atop {x=0}} \right\\\\a = (2^2 - 0^2) - (\frac{2^3}{3} - \frac{0^3}{3})\\\\a = 2^2 - \frac{2^3}{3}\\a = 4 - 8/3\\a \approx 1.333$