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2 years ago

PLS HELP!!!! Function 111 is defined by the equation r=\dfrac{5}{8}t-9r=

Mathematics

2 answers:

Gnom [1K]2 years ago

8 0

Answer:

they have the same as y

Step-by-step explanation:

khan<3

katrin [286]2 years ago

7 0

Answer:

Oh this is easy 21'-sid93dnsimepl-02

Step-by-step explanation:

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How to determine if a set of ordered pairs represents a function???

zheka24 [161]

when the value of one variable is related to the value of a second variable we have a relation

5 0

4 years ago

Please help me. I’m not smart.

klio [65]

Answer:

3/4 or 0.75

Step-by-step explanation:

the equation is in slope-intercept form

y=mx+b

where m is the slope and b is the y-intercept.

you have already found the y-intercept to be -2, so now we just have to find the slope.

slope is also known as rise/run. so if we start at the y-intercept of -2, we can rise (go up) 3 units and then run (go over) 4 units until we reach another point on the line.

so the slope is 3/4 which is also equal to 0.75 units

4 0

4 years ago

Simplify the following. 8 × -7

Jlenok [28]

Answer:

8*-7= -56

Step-by-step explanation:

How I solved it in my head

8*6= 48

48+7= 56

If you multiply any number with a negative, the answer becomes a negative

4 0

3 years ago

PLEASE HELPPPPPPPPPPPPPPPPPPPPPPPPP

sineoko [7]

Answer:

I'm pretty sure that it is A- The message travels through the spinal cord

Step-by-step explanation:

3 0

4 years ago

The diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm. How much bigger is the distance around a quarter

olga55 [171]

Answer:

9.577 mm.

Step-by-step explanation:

We have been given that the diameter of a quarter is 24.26 mm and the diameter of a nickel is 21.21 mm.

Let us find the circumference of quarter and nickel using circumference of circle formula.

$\text{Circumference of circle}=2\pi r$ , where r represents radius of the circle.

Since we know that diameter of circle is 2 times its radius, so let us find radius of quarter and nickel by dividing their diameter by 2.

$\text{Radius of quarter}=\frac{24.26}{2}$

$\text{Radius of quarter}=12.13$

$\text{Radius of nickel}=\frac{21.21}{2}$

$\text{Radius of nickel}=10.605$

$\text{Circumference of quarter}=2\times 3.14\times 12.13$

$\text{Circumference of quarter}=76.1764$

Therefore, circumference of quarter is 76.1764 mm.

Let us find circumference of nickel.

$\text{Circumference of nickel}=2\times 3.14\times 10.605$

$\text{Circumference of nickel}=66.5994$

Let us subtract circumference of nickel from circumference of quarter.

$\text{The difference between distance around quarter and nickel}=76.1764-66.5994$

$\text{The difference between distance around quarter and nickel}=9.577$

Therefore, the distance around a quarter is 9.577 millimeters bigger than a nickel.

7 0

4 years ago