Question

What is the solution of StartRoot x squared 49 EndRoot = x 5?.

Answer 1

The squiring numbers and square root number has inverse relationship.The square root and the square cancel each other.The value of the variable x of the given quadratic equation is 12/5 or 2.4

Given information-

The given equation in the problem is,

$\sqrt{x^2+49} =x+5$

Square both side of the above equation,

$(\sqrt{x^2+49})^2 =(x+5)^2$

Square and square root

The squiring numbers and square root number has inverse relationship. The square root and the square cancel each other. Thus,

$\begin{aligned}\\x^2+49 &=(x+5)^2\\x^2+49&=x^2+25+10x\\x^2-x^2+10x&=49-25\\10x&=24\\x&=\dfrac{24}{10} \\x&=\dfrac{12}{5} \\x&=2.4\end$

Hence the value of the variable x of the given quadratic equation is 12/5 or 2.4.

Learn more about the quadratic equation here;

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