The magnitude of each vector is the Pythagorean sum of its components.
a. |v1| = √(2² + (-6)²) = √40 = 2√10
|v2| = √((-4)² + 7²) = √65
b. To make each vector into a unit vector, divide each component by the vector's magnitude.
u1 = v1/|v1| = (2/(2√10), -6/(2√10))
u1 = (√10/10, -3√10/10)
u2 = v2/|v2| = (-4/√65, 7/√65)
u2 = (-4√65/65, 7√65/65)
Hello,
tan KLJ=6/8=3/4
=> mes angle KLJ=36.8698976558...°≈36.87 °
Answer B.
The missing exponent is 2
Answer:
y= CC-4.5x^2
Step-by-step explanation:
To find the general solution to the differential equation
dy + 9x dx = 0, we employ the method of separating variable as follows:
Note: { will represent the integral sign here.
Separating the variables and integrating, we have
{dy = -{9x dx
y = -(9/2)(x^2) + CC,
where CC is the given constant of integration.
This can be rearranged/simplified to yield
y= CC-4.5x^2
[A+7= 28] is the correct equation I believe, though I may be wrong.
