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3 years ago

11

If you have 8 batteries cost $40 [cost per battery]

2 answers:

Finger [1]3 years ago

5 0

Answer:

the answer is 5 because 40 divided by 8 is 5

insens350 [35]3 years ago

3 0

Answer: 5

Step-by-step explanation: 40 divided by 8= 5

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HELPPPPPPPPPPPPPP PLZZZZZZZZZZZZ

miss Akunina [59]

Answer:

The length of the base is 3.6 and the length of the height is 5.6. Therefore the area of the triangle is 1\2×5.6×3.6=20.16

Length×Width×1\2

3 0

3 years ago

What is the derivative of ln(lnx^3)

chubhunter [2.5K]

the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

<u>Step-by-step explanation:</u>

Here we have to find the derivative of ln(lnx^3) , Let's find out:

We have , $ln(lnx^3)$ , Let's differentiate it w.r.t x :

⇒ $\frac{d(ln(lnx^3))}{dx}$

Let $lnx^3 = u$

⇒ $\frac{d(ln(u))}{dx}$

⇒ $\frac{1}{u} (\frac{d(u)}{dx} )$

⇒ $\frac{1}{u} (\frac{d(ln(x^3))}{dx} )$

Let $x^3=v$

⇒ $\frac{1}{u} (\frac{d(ln(v))}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(v)}{dx} )$

⇒ $\frac{1}{u}(\frac{1}{v} ) (\frac{d(x^3)}{dx} )$

⇒ $3x^2(\frac{1}{u})(\frac{1}{v} )$

Putting value of u & v we get:

⇒ $3x^2(\frac{1}{lnx^3})(\frac{1}{x^3} )$

⇒ $\frac{3}{x(lnx^3)}$ { $lnx^n = n(lnx)$ }

⇒ $\frac{3}{3x(lnx)}$

⇒ $\frac{1}{x(lnx)}$

Therefore , the derivative of ln(lnx^3) is $\frac{1}{x(lnx)}$ .

6 0

3 years ago

Quadrilateral RPQS is a rectangle. Label the missing measures.

Taya2010 [7]

Answer:

Part 1) $PR=9\ units$

Part 2) $PQ=12\ units$

Part 3) $PS=15\ units$

part 4) $QR=15\ units$

Part 5) $RT=7.5\ units$

Step-by-step explanation:

we know that

In a rectangle opposite sides are parallel and congruent

The measure of each interior angle is 90 degrees

The diagonals are congruent and bisect each other

step 1

Find the length of side PR

we know that

$PR=QS$ ----> by opposite sides

we have

$QS=9\ units$

therefore

$PR=9\ units$

step 2

Find the length of side PQ

we know that

$PQ=RS$ ----> by opposite sides

we have

$RS=12\ units$

therefore

$PQ=12\ units$

step 3

Find the length of diagonal PS

we know that

$PS=2PT$ ---> the diagonals bisect each other

we have

$PT=7.5\ units$ ---> given problem

therefore

$PS=2(7.5)=15\ units$

step 4

Find the length of diagonal QR

we know that

$QR=PS$ ---> the diagonals are congruent

we have

$PS=15\ units$

therefore

$QR=15\ units$

step 5

Find the length of RT

we know that

$QR=2RT$ ---> the diagonals bisect each other

we have

$QR=15\ units$

substitute

$15=2RT\\RT=7.5\ units$

7 0

3 years ago

Which expressions are equivalent to 1 5 ⋅ 1 5 ⋅ 1 5 ⋅ 1 5 5 1 ⋅ 5 1 ⋅ 5 1 ⋅ 5 1 start fraction, 1, divided by, 5, end fr

Sergio039 [100]

Answer:

The possible expressions are:

$\frac{1}{5} X \frac{1}{5} X \frac{1}{5}X \frac{1}{5}$

$\frac{1}{5^4}$

$\frac{1}{625}$

Step-by-step explanation:

We are to determine the expression equivalent to:

$\frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5}\cdot \frac{1}{5}$

Since the options are not listed, I would give you possible answers.

$\frac{1}{5} \cdot \frac{1}{5} \cdot \frac{1}{5}\cdot \frac{1}{5} = \frac{1}{5} X \frac{1}{5} X \frac{1}{5}X \frac{1}{5}$

$\frac{1}{5} X \frac{1}{5} X \frac{1}{5}X \frac{1}{5}=(\frac{1}{5})^4=\frac{1^4}{5^4}=\frac{1}{5^4}$

$\frac{1}{5} X \frac{1}{5} X \frac{1}{5}X \frac{1}{5}=\frac{1}{625}$

4 0

4 years ago

I pass through (-2,5). I pass through the origin. What’s my equation?

rosijanka [135]

Slope = 5/-2 = -2.5
<span>pass through the origin (0,0)
</span>so equation
y = -2.5x

7 0

3 years ago