If you have 8 batteries cost $40 [cost per battery]

Find the value of X to the nearest tenth:

castortr0y [4]

Answer:

13.0

Step-by-step explanation:

sin(65°) × 14.3 would give u 12.9 then u round it to the 13

5 0

3 years ago

Please help me....))

miskamm [114]

The first picture is for number 1 and the second one for number 2.

8 0

2 years ago

There will be 6 people at ellies pie party she wants to bake enough pie so each person can eat at least 1/5 of pie what is the m

tatyana61 [14]

Answer:

2

Step-by-step explanation:

She needs to have 6 portions of 1/5 pie size.

6 portions of 1/5 pie size is 6/5 of a pie.

6/5 of a pie is the same as 1 1/5 (one and one-fifth) pies.

Since she only bakes full pies, she must round up to the next higher whole number, so she must bake 2 pies.

8 0

3 years ago

Jenny bought 3 CDs that were each the same price. Including sales tax, she paid a total of $45.30 Of that total, $1.50 was tax.

enot [183]

Answer:

$13.6

Step-by-step explanation:

Jane bought 3 CDs that were each the same price. So let the price of each CD be ‘x’.

It is given that including sales tax, she paid a total of $45.30.

Also each CD had a tax of $1.50. We need to find out what the price of each CD was before tax.

Since the tax for all 3 CDs was same, the total amount of tax that she paid was:

3 * 1.50 = 4.50

Therefore the total tax on 3 CDs is $4.50

Since we already know the total price she paid for the CDs including taxes, we can find the price of each CD by the following way:

3x + 4.50 = 45.30

3x = 45.30 - 4.50

3x = 40.8

x = 13.6

Therefore the price of each CD before tax is $13.6.

5 0

3 years ago

Consider testing H^0: u=20 against H^a: u<20 where u is the mean number of latex gloves used per week by all hospital employe

iragen [17]

Answer:

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

Step-by-step explanation:

Data given and notation

$\bar X=19.1$ represent the sample mean

$s=11.8$ represent the sample standard deviation

$n=46$ sample size

$\mu_o =20$ represent the value that we want to test

$\alpha=0.01$ represent the significance level for the hypothesis test.

t would represent the statistic (variable of interest)

$p_v$ represent the p value for the test (variable of interest)

State the null and alternative hypotheses.

We need to conduct a hypothesis in order to check if the mean is lower than 20, the system of hypothesis would be:

Null hypothesis: $\mu \geq 20$

Alternative hypothesis: $\mu < 20$

If we analyze the size for the sample is > 30 but we don't know the population deviation so is better apply a t test to compare the actual mean to the reference value, and the statistic is given by:

$t=\frac{\bar X-\mu_o}{\frac{s}{\sqrt{n}}}$ (1)

t-test: "Is used to compare group means. Is one of the most common tests and is used to determine if the mean is (higher, less or not equal) to an specified value".

Calculate the statistic

We can replace in formula (1) the info given like this:

$t=\frac{19.1-20}{\frac{11.8}{\sqrt{46}}}=-0.517$

Part a: P-value

The first step is calculate the degrees of freedom, on this case:

$df=n-1=46-1=45$

Since is a one sided test the p value would be:

$p_v =P(t_{(45)}$

Part b: Conclusion

If we compare the p value and the significance level given $\alpha=0.01$ we see that $p_v>\alpha$ so we can conclude that we have enough evidence to fail reject the null hypothesis, and we can conclude that the true mean is not lower than 20 at 1% of signficance.

a. There is insufficient evidence to reject h^0

5 0

3 years ago