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tatiyna
2 years ago
8

Please answer it....

Mathematics
1 answer:
valentinak56 [21]2 years ago
4 0

The third ordered pair that satisfy the given equation is (123, 369).

The given parameters;

  • a^2 + b^2 = 10(123)^2
  • <em>First pair of the equation, = (39, 387)</em>
  • <em>Second pair of the equation = (201, 333).</em>

The third ordered pair of the equation can be determined by using general equation of a circle;

a^2 + b^2 = r^2\\\\a^2 + b^2 = (123\sqrt{10} )^2\\\\a^2 + b^2 = (\sqrt{151290} )^2\\\\a^2 + b^2 = 151290\\\\a^2 = 151290- b^2\\\\ a= \sqrt{151290 - b^2}

The radius of the circle is calculated as;

r^2 = 151290\\\\r = \sqrt{151290} \\\\r = 388.96

The value of a can be obtained by randomly choosing numbers less than the radius as values of b.

b < r\\\\b < 388.96

a = \sqrt{151290 \ - \ (387)^2} \\\\a = 39\\\\(39, \ 387)\\\\a = \sqrt{151290 \ - \ (333)^2}\\\\a = 201\\\\(201, \ 333)\\\\a = \sqrt{151290 \ - \ (369)^2}\\\\a = 123\\\\(123, \ 369)

Thus, the third ordered pair that satisfy the given equation is (123, 369).

Learn more about equation of circle here: brainly.com/question/1506955

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<h3>What is the highest common factor?</h3>

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