We have two unknowns: x and y. Now, we have to formulate 2 equations. The first would come from the use of the given ratio:
We use the distance formula to find the distance between coordinates:
3/4 = √[(x-4)²+(y-1)²] / √[(4-12)²+(1-5)²]
√[(x-4)²+(y-1)²] = 3√5
(x-4)²+(y-1)² = 45
x² - 8x + 16 + y² - 2y + 1 = 45
x² - 8x + y² - 2y = 28 --> eqn 1
The second equation must come from the equation of a line:
y = mx +b
m = (5-1)/(12-4) = 1/2
Substitute y=5 and x=12 for point (12,5)
5 = (1/2)(12) + b
b = -1
So, the second equation is
y = 1/2x -1 or x = 2 + 2y --> eqn 2
Solving the equations simultaneously:
(2 + 2y)² - 8(2 + 2y) + y² - 2y = 28
Solving for y,
y = -2
x = 2+2(-2) = -2
Therefore, the coordinates of point A is (-2,-2).
Answer: 195
Step-by-step explanation:
Cost per student = $4
Total number who attended = n
The cost of the total of student who attended will be cost per student multiplied by the total number of students, that is
Total cos = 4n
Since, they are to pay $140 , for publicity, then the total cost becomes
T = 4n - 140
From the last statement
4n - 140 ≥ 640
4n ≥ 640 + 140
4n ≥780
n ≥ 780/4
n ≥ 195
That means at least 195 students must attend if the science club is to earn at least $ 640
Answer:
Blurry
Step-by-step explanation:
Answer:
x = -3 and y = -4
x + y = -3-4 = -7
Step-by-step explanation:
-4x + 9y = -11 ------------------------------------------------------------------------(1)
-3x + 7y = -9--------------------------------------------------------------------------(2)
multiply through equation (1) by 3 and multiply through equation(2) by 4
-12x + 27y = -33 -----------------------------------------------------------------------(3)
-12x + 28y = -36 ----------------------------------------------------------------------(4)
subtract equation (1) from equation (2)
y = -3
substitute y = -3 into equation (2)
-3x + 7(-3) = -9
-3x -21 = -9
add 21 to both-side of the equation
-3x -21 + 21 = -9 + 21
-3x = 12
divide both-side of the equation by -3
-3x/-3 = 12/-3
x = -4
x = -3 and y = -4
<h2>ANSWER:</h2><h3>Non Elements</h3><h3 /><h2>NOTES:</h2><h3>With the exception of HYDROGEN, the elements on the left side of the periodic table are METALS. Elements on the right side of the periodic table are NONMETALS.</h3>
