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Tasya [4]
2 years ago
6

I will brainlist who can answer this 2 question!

Mathematics
1 answer:
LUCKY_DIMON [66]2 years ago
3 0
Where’s the question?
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Ed has some money. He spends £7.50 on a shirt and now has one-third of what he started with.
svlad2 [7]

Answer:

x- 7.50 i think i hope i helped

Step-by-step explanation: there no explanation

7 0
3 years ago
A model rocket is launched from the ground with an initial velocity of 160 ft/sec. how long will it take the rocket to reach its
timama [110]
The formula we need is
h(t)=-16t^2+v_0 t+h_0, where <em>v</em>₀ is the starting velocity and <em>h</em>₀ is the initial height.  Using the velocity and starting height from our problem we have
h(t)=-16t^2+160t+0.  The path of this rocket will be a downward facing parabola, so there will be a maximum.  This maximum will be at the vertex of the graph.  To find the vertex we start out with x= \frac{-b}{2a}, which in our case is x= \frac{-160}{2(-16)}= \frac{-160}{-32} = 5.  It will take 5 seconds for the rocket to reach its maximum height.  Plugging this back into our formula gives us
h(5)=-16(5^2)+160(5)+0&#10;\\=-16(25)+800&#10;\\=-400+800=400
The rocket's maximum height is 400 feet.
We set our formula equal to zero to find the time it takes to hit the ground, then we factor:
0=-16t^2+160t+0&#10;\\0=-16t^2+160t&#10;\\0=-16t(t-10)
Using the zero product property, we know that either -16t =0 or t-10=0.  When -16t=0 is at t=0, when the rocket is launched. t-10=0 gives us an answer of t=10, so the rocket reaches the ground again at 10 seconds.
8 0
3 years ago
PLEASE HELP whats the hypotenuse of a right triangle if both its legs are 9 cm round to the nearest tenth of a cm
vivado [14]
Pythagorean theorem: a² + b² = c² 

a² and b² are the legs, and c² is the hypotenuse.

Plug in 9 to a² and b² since you know that both the right triangle's legs are 9 cm.

9² + 9² = c²
81 + 81 = c²
162 = c²

Square root both sides.

c = 12.7 cm
6 0
4 years ago
Order from greatest to least 10.9, 10 2/5, 10 1/4
Ede4ka [16]

Answer:10.9,,,,,10 2/5,,,,,10 1/4

Step-by-step explanation:

3 0
3 years ago
What is the solution of 5sin2θ=3 for 0≤θ≤2π? Please help.
grigory [225]

Answer:

C) \theta\approx\{0.3218,1.249,3.463,4.3908\}

Step-by-step explanation:

5\sin2\theta=3;\: 0\leq\theta\leq 2\pi\\\\\sin2\theta=\frac{3}{5}\\ \\2\theta\approx\{0.6436,2.498,6.926,8.7816\}\\\\\theta\approx\{0.3218,1.249,3.463,4.3908\}

7 0
2 years ago
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