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hram777 [196]
2 years ago
9

Sam was still finishing his breakfast when his brother Leo left for school. Sam started to run after Leo when Leo was already 10

0 meters away. How soon will Sam catch up with Leo, if he is running at a speed of 105 meters per minute while Leo is walking at a speed of 65 meters per minute?
Mathematics
1 answer:
Bas_tet [7]2 years ago
3 0

Answer:

X=2.5 min

Y=262.5 m

Step-by-step explanation:

Let x be the time ( in minutes ) Sam will take to catch Leo .

We know that : Distance = Speed x Time

Speed of Leo = 65 meters per minute

Speed of Sam = 105 meters per minute

According to the given situation, we have

Distance covered by Leo = (100 +65 x ) meters

Distance covered by Sam = 105 x meters

Sam will catch Leo when distance covered by Leo would be equal to  distance covered by Sam.  

 [ Subtract 65 x from both sides ]

x=2.5    [Divide both sides by 40]

therefore Sam will catch up Leo after 2.5 minutes.

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Answer:

\huge\boxed{77}

Step-by-step explanation:

The number can be divisible by 7.

The multiples of 7 are 7,14,21,28,35,42,49,56,63,70,77,84 and so on

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21 => 1,3,7,21   [4 factors but Sum = 32]

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35 => 1,5,7,35   [4 factors but Sum = 48]

42 => 1, 2, 3, 6, 7, 14, 21, 42     [Not 4]

49 => 1,7,49   [Not 4]

56 => 1, 2, 4, 7, 8, 14, 28, 56       [Not 4]

63 => 1, 3, 7, 9, 21, 63     [Not 4]

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Put the value of x in equation (1)

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The solution is also shown in the attached figure. Hence, the solution is x = -1 and y = -1.

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