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3 years ago

13

The function f(x)=x−5 x 2−25 is defined everywhere except at x=±5. if possible, define f at x=5 so that it becomes continuous at

x=5.\

1 answer:

Bogdan [553]3 years ago

5 0

The answer is the number 23

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For the function f(x)=<img src="https://tex.z-dn.net/?f=%5Cfrac%7B%5Csqrt%7Bx%7D%20%7D%7B5%7D%20%2B2" id="TexFormula1" title="\f

Ber [7]

Answer:

$f^{-1}(x)=25(x-2)^2$

Step-by-step explanation:

The inverse function can be found by solving ...

f(y) = x

(√y)/5 +2 = x

(√y)/5 = x -2 . . . . . subtract 2

√y = 5(x -2) . . . . . . multiply by 5

y = 25(x -2)² . . . . . square both sides

The inverse function is ...

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