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zvonat [6]
3 years ago
13

The function f(x)=x−5 x 2−25 is defined everywhere except at x=±5. if possible, define f at x=5 so that it becomes continuous at

x=5.\
Mathematics
1 answer:
Bogdan [553]3 years ago
5 0
The answer is the number 23
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6 1⁄3 + 7 1⁄4 – 2 1⁄2 =
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Answer:

11 1/12

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6 0
3 years ago
18 2by5-4 1by10 find the difference
luda_lava [24]

Given:

The expression is:

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18\dfrac{2}{5}-4\dfrac{1}{10}

It can be rewritten as:

=\dfrac{90+2}{5}-\dfrac{40+1}{10}

=\dfrac{92}{5}-\dfrac{41}{10}

Taking LCM, we get

=\dfrac{184-41}{10}

=\dfrac{143}{10}

=\dfrac{140+3}{10}

=14\dfrac{3}{10}

Therefore, the value of the difference is 14\dfrac{3}{10}.

3 0
3 years ago
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