The function f(x)=x−5 x 2−25 is defined everywhere except at x=±5. if possible, define f at x=5 so that it becomes continuous at
1 answer:
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Area of a rectangle is
(7.4×5.5)m
=40.7m
therefore the area of the room is 40.7m
(7.4×5.5)m
=40.7m
therefore the area of the room is 40.7m
Answer:
The value x in the equation 50=14+x+7+2x-1 is 10
Step-by-step explanation:
Given that the length of one side of a triangle is 14 inches
Let a be the length of one side
Therefore a=14 inches
The length of second side in x+7 inches
Let b be the length of second side
b=x+7 inches.
The length of third side is 2x-1 inches
Let c be the length of third side
c=2x-1 inches
And perimeter of the triangle =50 inches
Perimeter of a triangle =a+b+c
Equation can be written as
50=14+x+7+2x-1
50=20+3x ( adding the like terms )
Rewritting as below
3x+20=50
3x+20-50=50-50
3x-30=0
3x-30+30=0+30
3x=30
Therefore x=10
The value of x is 10