-First we have to work out what’s in parenthesis.
(8*10^-3)=(8*0.001)=0.008
-This is for the second parenthesis
(2*10^-4)=(2*0.0001)=0.0002
-Now we multiply them together
ANSWER: 0.0000016
There's more than one way to combine them really
but an obvious one will be
![\bf \begin{array}{llll} h(x)&=&(f\circ g)(x)\\\\ &&\sqrt[3]{7x+1}\\\\ &&\sqrt[3]{g(x)}\leftarrow \begin{array}{llll} f(x)=\sqrt[3]{x }\\\\ g(x)=7x+1 \end{array} \end{array}\\\\ -----------------------------\\\\ (f\circ g)(x)\iff f[\quad g(x)\quad ]=\sqrt[3]{g(x)}\implies f[\quad g(x)\quad ]=\sqrt[3]{7x+1}](https://tex.z-dn.net/?f=%5Cbf%20%5Cbegin%7Barray%7D%7Bllll%7D%0Ah%28x%29%26%3D%26%28f%5Ccirc%20g%29%28x%29%5C%5C%5C%5C%0A%26%26%5Csqrt%5B3%5D%7B7x%2B1%7D%5C%5C%5C%5C%0A%26%26%5Csqrt%5B3%5D%7Bg%28x%29%7D%5Cleftarrow%20%0A%5Cbegin%7Barray%7D%7Bllll%7D%0Af%28x%29%3D%5Csqrt%5B3%5D%7Bx%20%7D%5C%5C%5C%5C%0Ag%28x%29%3D7x%2B1%0A%5Cend%7Barray%7D%0A%5Cend%7Barray%7D%5C%5C%5C%5C%0A-----------------------------%5C%5C%5C%5C%0A%28f%5Ccirc%20g%29%28x%29%5Ciff%20f%5B%5Cquad%20g%28x%29%5Cquad%20%5D%3D%5Csqrt%5B3%5D%7Bg%28x%29%7D%5Cimplies%20%20f%5B%5Cquad%20g%28x%29%5Cquad%20%5D%3D%5Csqrt%5B3%5D%7B7x%2B1%7D)
Basically solve for y
minus 5x fromboth sides
-15y=-5x-60
divide both sides by -15
y=1/3x+4
<u><em>Answer: </em></u>
#9: 5
#10: -2
#11: -1.5
<em><u>Step-by-step explanation:</u></em>
<em><u>#9:</u></em> 3,8,13,18,23,(28),(33),(38),.. <em>Go up by 5 each time, so the common difference is </em><u><em>5</em></u><em>.</em>
<u><em>#10:</em></u> 11,9,7,5,3,(1),(-1),(-3),... <em>Go down </em><em>(-)</em><em> by 2 each time, so the common difference is </em><u><em>-2</em></u><em>.</em>
<u><em>#11:</em></u> 3, 1.5, 0, -1.5, -3, (-4.5), (-6), (-7.5),... <em>Go down </em><em>(-) </em><em>by 1.5 each time, so the common difference is </em><u><em>-1.5</em></u><em>.</em>
Answer:
When dividing rational numbers, multiply by the "right" reciprocal. In this case, the "right" reciprocal means to take the reciprocal of the fraction on the right-hand side of the division operator.
