40 divided by 33n. hope it helps!
Answer:
p(on schedule) ≈ 0.7755
Step-by-step explanation:
A suitable probability calculator can show you this answer.
_____
The z-values corresponding to the build time limits are ...
z = (37.5 -45)/6.75 ≈ -1.1111
z = (54 -45)/6.75 ≈ 1.3333
You can look these up in a suitable CDF table and find the difference between the values you find. That will be about ...
0.90879 -0.13326 = 0.77553
The probability assembly will stay on schedule is about 78%.
For this case we first calculate the rate in blocks per minutes.
rate = (15.5) / (35) = 0.443 blocks per minutes.
Then, we can go to blocks per hour.
Remember: 1h = 60min.
rate = 0.443 * (1/60) = 0.00738 blocks per hour.
answer
his rate in blocks per hour is 0.00738 blocks per hour.