All categories

3 years ago

Some please help, select all the intervals where g is increasing

Mathematics

2 answers:

taurus [48]3 years ago

7 0

Answer:

$( - inf, - 3.5) \\ ( - 1, 2.5)$

These are interval for increasing (doesnt include relative max-min)

Step-by-step explanation:

Increasing means when we input the value of x and we get the increase of y-value.

A bit hard to imagine? You can look at the graph instead. The name already says it all, Increasing Graph. The graph keeps rising and rising till the max and that is increasing.

The decreasing is when the graph decreases to minimum. The graph would face down for decreasing.

Since we only want the increasing. We look at the graph and tell which region does the graph face up and that is the increasing.

noname [10]3 years ago

7 0

Answer:

Step-by-step explanation:

You might be interested in

-3x-3y=3 and y=5x-17

Vesna [10]

The answer for this question is "y = -5/3 and x = 8/3"

5 0

3 years ago

Which is the inverse of the function a(d)=5d-3? And use the definition of inverse functions to prove a(d) and a-1(d) are inverse

Drupady [299]

Answer:

$a'(d) = \frac{d}{5} + \frac{3}{5}$

$a(a'(d)) = a'(a(d)) = d$

Step-by-step explanation:

Given

$a(d) = 5d - 3$

Solving (a): Write as inverse function

$a(d) = 5d - 3$

Represent a(d) as y

$y = 5d - 3$

Swap positions of d and y

$d = 5y - 3$

Make y the subject

$5y = d + 3$

$y = \frac{d}{5} + \frac{3}{5}$

Replace y with a'(d)

$a'(d) = \frac{d}{5} + \frac{3}{5}$

Prove that a(d) and a'(d) are inverse functions

$a'(d) = \frac{d}{5} + \frac{3}{5}$ and $a(d) = 5d - 3$

To do this, we prove that:

$a(a'(d)) = a'(a(d)) = d$

Solving for $a(a'(d))$

$a(a'(d)) = a(\frac{d}{5} + \frac{3}{5})$

Substitute $\frac{d}{5} + \frac{3}{5}$ for d in $a(d) = 5d - 3$

$a(a'(d)) = 5(\frac{d}{5} + \frac{3}{5}) - 3$

$a(a'(d)) = \frac{5d}{5} + \frac{15}{5} - 3$

$a(a'(d)) = d + 3 - 3$

$a(a'(d)) = d$

Solving for: $a'(a(d))$

$a'(a(d)) = a'(5d - 3)$

Substitute 5d - 3 for d in $a'(d) = \frac{d}{5} + \frac{3}{5}$

$a'(a(d)) = \frac{5d - 3}{5} + \frac{3}{5}$

Add fractions

$a'(a(d)) = \frac{5d - 3+3}{5}$

$a'(a(d)) = \frac{5d}{5}$

$a'(a(d)) = d$

Hence:

$a(a'(d)) = a'(a(d)) = d$

7 0

3 years ago

Would these be similar?

const2013 [10]

Hey buddy I am here to help!

Yes these r similar!

Hope this helps!

Plz mark me brainliest!

8 0

3 years ago

Read 2 more answers

Please Help Meeeeeeeeeee

Darya [45]

Answer:

hxhxhxh jsjsjsj jdjdjd

6 0

3 years ago

6x - 10y = -16<br><br> x + 20y = 19

Lena [83]

This may be the right answer: x=-1 y=-11/5

4 0

3 years ago