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Llana [10]
2 years ago
12

The area of a rectangular painting is 5,355 cm, if the width of the painting is 63 centimeters, what is its length?

Mathematics
1 answer:
drek231 [11]2 years ago
4 0

Answer:

Length is 85 cm.

Step-by-step explanation:

area= l*w

l = area/ w

Basically, 5355/63 = 85

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You flip a coin and then roll a fair six-sided die. Find probability the coin lands heads-up and the die shows a five
stepladder [879]

Answer:

5 cent

Step-by-step explanation:

4 0
3 years ago
Read 2 more answers
Quadrilateral LMNO is similar to quadrilateral PQRS. Find the measure of side QR.
dalvyx [7]

Answer:

The measure of the side QR is 8.8.

Step-by-step explanation:

Since LMNO \sim PQRS, then SP \propto OL, RS \propto ON, RQ \propto MN and QP \propto LM. From figure we have the following relationship:

k = \frac{OL}{SP} = \frac{ON}{RS} = \frac{MN}{QR} = \frac{ML}{QP} (1)

Where k is the proportionality ratio.

If we know that SP = 13, OL = 55, MN = 37, then the measure of side QR is:

k = \frac{OL}{SP} (1b)

k = \frac{55}{13}

k = \frac{MN}{QR}

QR = \frac{MN}{k} (1c)

QR = \frac{37}{\frac{55}{13} }

QR = 8.745

The measure of the side QR is 8.8.

4 0
3 years ago
Question 8 of 25<br> Which of the following is the quotient of the rational expressions shown here?
Alla [95]

Answer:

  B.  (5x+5)/(x²-2x)

Step-by-step explanation:

As with numerical fractions, division by a rational expression is equivalent to multiplication by its reciprocal.

<h3>As a multiplication problem</h3>

  \dfrac{5}{x-2}\div\dfrac{x}{x+1}=\dfrac{5}{x-2}\times\dfrac{x+1}{x}

<h3>Product of rational expressions</h3>

As with numerical fractions, the product is the product of numerators, divided by the product of denominators.

  =\dfrac{5(x+1)}{x(x-2)}=\boxed{\dfrac{5x+5}{x^2-2x}}

4 0
2 years ago
Gregory knows that Triangle A B C is reflected onto Triangle A prime B prime C prime. Which statement about the figures is true?
ziro4ka [17]
Answer: if Gregory draws the segment with endpoints A and A’, then the midpoint will lie on the line of reflection.

Explanation:

Given that a triangle ABC is reflected in triangle A'B'C'

Here reflection is done on a line

If you imagine the line as a mirror then ABC will have image on the mirror line as A'B'C'

Recall that in a mirror the object and image would be equidistant from the mirror and also the line joining the image and object would be perpendicular to the mirror

But note that corresponding images will only be perpendicular bisector to the line

So A and A' only will be corresponding so AA' will have mid point on line

Option 1 is right
5 0
3 years ago
HELP NEEEEED HELP !( POINTS PLEASE RIGHT ANSWER???????????????
Ivan

Answer:

Lydia

Step-by-step explanation:

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