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Scorpion4ik [409]
2 years ago
14

Your restaurant can seat 150 guests. If 6 tables of 6 are seated, what percent of the restaurant seating is still empty?

Mathematics
2 answers:
Anettt [7]2 years ago
7 0

Answer:

76% of the restaurant is still empty

Step-by-step explanation:

6 tables of 6 seated means there are currently 36 people seated. If the restaurant can seat 150 people, 76% of the restaurant is still empty.

6\times6=36\text{ | there are 36 guests}\\36\div150=0.24\text{ | 24\% of the restaurant is filled}\\1-0.24=0.76\text{ | 76\% of the restaurant is not filled}

nikitadnepr [17]2 years ago
5 0

Answer:

76%

Step-by-step explanation:

First, we know that 6 tables of 6 are already seated. We can go ahead and multiply 6 by 6, which is 36.

This means that 36 of the 150 seats are already taken.

But, we want to find the amount of seats that are still empty. So, we subtract 36 from 150 to get 114 seats.

The question is asking for the percentage, so we can divide 114 by 150 seats to get 0.76. Then, we have to move the decimal to the right 2 spaces to get 76%

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Answer:

  P'(4, 9)

Step-by-step explanation:

Add the translation vector to the point:

  P' = P +(6, 5) = (-2, 4) +(6, 5) = (-2+6, 4+5)

  P' = (4, 9)

4 0
2 years ago
Tim sold half of his comic books then bought 8 more. He now has 17. How many did he start with?
disa [49]

Answer:

18

Step-by-step explanation:

18 divided by 2 is 9 plus 8 is 17

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3 years ago
An urn contains 5 red balls and 2 green balls. Two balls are drawn one after the other. What is the probability that the second
AleksAgata [21]

Answer:

<em>The probability that the second ball is red is 71%</em>

Step-by-step explanation:

<u>Probabilities</u>

We know there are 5 red balls and 2 green balls. Let's analyze what can happen when two balls are drawn in sequence (no reposition).

The first ball can be red (R) or green (G). The probability that it's red is computed by

\displaystyle P(R)=\frac{5}{7}

The probability is's green is computed by

\displaystyle P(G)=\frac{2}{7}

If we have drawn a red ball, there are only 4 of them out of 6 in the urn, so the probability to draw a second red ball is

\displaystyle P(RR)=\frac{5}{7}\cdot \frac{4}{6}=\frac{10}{21}

If we have drawn a green ball, there are still 5 red balls out of 6 in the urn, so the probability to draw a red ball now is

\displaystyle P(GR)=\frac{2}{7}\cdot \frac{5}{6}=\frac{5}{21}

The total probability of the second ball being red is

\displaystyle P(XR)=\frac{10}{21}+\frac{5}{21}=\frac{5}{7}=0.71

The probability that the second ball is red is 71%

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3 years ago
Help please, not sure how to do this...​
olga nikolaevna [1]

Answer:

8.38

Step-by-step explanation:

The underlined number is in the hundredths place, so that means that we're going to round there. That means that you look at the number to its right and if it's lower than 5, it stays the same. However, if it's 5 or higher, you round it up. For example, if the number was 8.386, we would round it to 8.39.

5 0
3 years ago
What number goes on top and how do you solve it.
vekshin1
So basically, each number is equal to the two numbers below it added together.

See, 7 = 3+4, 8 = 5 +3, etc.

So, the top would be 16 + 17.

16 + 17 = 33

So 33 goes on top.
4 0
3 years ago
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