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tankabanditka [31]
3 years ago
8

ben uses 3/12 pound of strawberries and 2/12 pound of blueberries to make jam. how many pounds of berries does ben use to make j

am? A. 1/12 B. 5/24 C. 5/12 D. 1/2 FIRST ONE WHO ANSWERS GETS BRAINLIEST!!!!
Mathematics
2 answers:
aleksandrvk [35]3 years ago
6 0
The answer is 5/12 because 2+3 is 5 and your denominator stays the same and you don't change the denominator
torisob [31]3 years ago
5 0
5/12
3/12+2/12=5/12
The denominator is the same so you add the numerators.


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A cerise box has a height of 32 centimeters. It has a base with an area of 160 square centimeters. What is the volume, in cubic
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Answer:

5,120 cm³

Step-by-step explanation:

Volume = Base area × height

Base area = 160 cm²

Height = 32 cm

Vol. = 160 × 32

= 5,120 cm³

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Michael can spend a maximum of $234 on office supplies. Each ream of paper costs $6. Each ink cartridge costs $18. Which of the
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5 0
3 years ago
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Find the area of the shaded region. Show all of your work.
mihalych1998 [28]

Answer:

8in

Step-by-step explanation:

8 0
2 years ago
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How do you write 0.045 as a reduced fraction
Anvisha [2.4K]
0.045 = 45/1000

Divide top and bottom by their greatest common factor.
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3 years ago
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Explain the circumstances for which the interquartile range is the preferred measure of dispersion. What is an advantage that th
KatRina [158]

Answer:

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

Step-by-step explanation:

Previous concepts

The interquartile range is defined as the difference between the upper quartile and the first quartile and is a measure of dispersion for a dataset.

IQR= Q_3 -Q_1

The standard deviation is a measure of dispersion obatined from the sample variance and is given by:

s=\sqrt{\frac{\sum_{i=1}^n (X_i -\bar X)^2}{n-1}}

Solution to the problem

Explain the circumstances for which the interquartile range is the preferred measure of dispersion

Interquartile range is preferred when the distribution of data is highly skewed (right or left skewed) and when we have the presence of outliers. Because under these conditions the sample variance and deviation can be biased estimators for the dispersion.

What is an advantage that the standard deviation has over the interquartile​ range?

The most important advantage is that the sample variance and deviation takes in count all the observations in order to calculate the statistic.

8 0
3 years ago
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