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Luda [366]
2 years ago
15

The figure here shows triangle AOC inscribed in the region cut from the parabola y=x^2 by the line y=a^2. Find the limit of the

ratio of the area of the triangle to the area of the parabolic region as a approaches zero.

Mathematics
1 answer:
aleksandrvk [35]2 years ago
3 0
Area of the parabolic region = Integral of [a^2 - x^2 ]dx | from - a to a =

(a^2)x - (x^3)/3 | from - a to a = (a^2)(a) - (a^3)/3 - (a^2)(-a) + (-a^3)/3 =

= 2a^3 - 2(a^3)/3 = [4/3](a^3)

Area of the triangle = [1/2]base*height = [1/2](2a)(a)^2 = <span>a^3

ratio area of the triangle / area of the parabolic region = a^3 / {[4/3](a^3)} =

Limit of </span><span><span>a^3 / {[4/3](a^3)} </span>as a -> 0 = 1 /(4/3) = 4/3
</span>
 



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(Missing part of the question is attached)

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Suppose the only information we know about the function is:

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<h3>(a)</h3>

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<h3>(b)</h3>

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