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DanielleElmas [232]
3 years ago
14

The approximate mass of Mars is 6.42 X 10^23 kg write this mass and standard notation

Mathematics
2 answers:
Sauron [17]3 years ago
8 0

Answer:

642,000,000,000,000,000,000,000 kg

Step-by-step explanation: Basically you are multiplying 6.42 by 100,000,000,000,000,000,000,000. That looks really intimidating but it is very simple. All you have to do is move the decimal 23 hops to the right. Moving it to the right makes the number big, were moving it to the left makes the number smaller. We want a bigger number because we are writing the number in standard notation. Right now it is in scientific notation form (scientific notation is used because it is easier and quicker to write than writing 21 zeros).

Art [367]3 years ago
7 0

Answer:= 1.665 × 101

Step-by-step explanation:Answer:

= 1.665 × 101

(scientific notation)

= 1.665e1

(scientific e notation)

= 16.65 × 100

(engineering notation)

(one)

i hope it help!

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I am in middle school

Step-by-step explanation:

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3 years ago
Given that 18f = 33g, identify the ratio off to g in simplest form.
Kobotan [32]

Answer:

11/6

Step-by-step explanation:

18f = 33g

f/g = 33/18 = 11/6

8 0
3 years ago
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Cos (90-theta) • cosec90-theta) =tano. How?​
denis-greek [22]

Answer:

<u>______________________________________________________</u>

<u>TRIGONOMETRY IDENTITIES TO BE USED IN THE QUESTION :-</u>

For any right angled triangle with one angle α ,

  • \cos (90 - \alpha  ) = \sin \alpha  or  \sin(90 - \alpha ) = \cos\alpha
  • cosec \: (90 - \alpha  ) = \sec\alpha   or  \sec(90 - \alpha ) = cosec\:\alpha

<u>SOME GENERAL TRIGNOMETRIC FORMULAS :-</u>

  • <u></u>\sin \alpha = \frac{1}{cosec \: \alpha }  or  cosec \: \alpha  = \frac{1}{\sin \alpha }
  • <u></u>\cos \alpha = \frac{1}{\sec \alpha }  or  \sec \alpha = \frac{1}{\cos \alpha }

<u>______________________________________________________</u>

Now , lets come to the question.

In a right angled triangle , let one angle be α (in place of theta) .

So , lets solve L.H.S.

\cos (90 - \alpha ) \times cosec(90 - \alpha )

=> sin\alpha  \times \sec\alpha

=> \sin\alpha  \times \frac{1}{\cos\alpha }

=> \frac{\sin\alpha }{\cos\alpha }

=> \tan\alpha = R.H.S.

∴ L.H.S. = R.H.S. (Proved)

3 0
3 years ago
Suppose triangle TIP and triangle TOP are isosceles triangles. Also suppose that TI=5, PI=7, and PO=11. What are all the possibl
taurus [48]
<h3>Two answers: 5, 7</h3>

====================================================

Explanation:

A drawing may be helpful to see what's going on. Check out the diagram below. This is one way of drawing out the two triangles. The locations of the points don't really matter, and neither does the the orientation of how you rotate things. What does matter is we have the right points connected to form the segments mentioned.

----------

For now, focus on triangle TIP only. In order to have this be isosceles, we must make TP = 5 or TP = 7.

If TP = 5, then it's the same length as TI.

If TP = 7, then it's the same length as PI.

In either case, we have exactly two sides the same length (the other side different) which is what it means for a triangle to be isosceles.

----------

Let's consider triangle TOP. For it to be isosceles, we must have two sides the same length. We already locked in TP to be either 5 or 7 in the previous section above. So there's no way that TP could be 11 units long to match up with PO = 11.

If TP = 5, then OT must also be 5 units long so that triangle TOP is isosceles.

If TP = 7, then OT = 7 for similar reasoning.

Either way, TP only has two choices on what it could be.

----------

In short, we basically just write the first two values given to us to get the two triangles to be isosceles. We can't use TP = 11 as it would make triangle TIP to be scalene (all sides are different lengths).

5 0
4 years ago
What is the answer????
Vinil7 [7]

Answer:

C. Parallelogram and rectangle

Step-by-step explanation:

If it was a square...all the sides would be the same, so it cannot be a square, therefore it is not A or B

3 0
3 years ago
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