I need help btw im 6th grader

You wish to borrow $8000 for debt consolidation. The bank's interest rate for a personal loan is 7.2%. What is your monthly paym

Lisa [10]

<h3>The monthly payment is $242.44 for loan to paid off in 3 years.</h3>

Step-by-step explanation:

The amount borrowed = Principal = $8000

The rate of interest = 7.2%

Time (T) = 3 years

Now, Simple Interest = $\frac{P\times R \times T}{100}$

$\implies SI = \frac{8000 \times 7.2 \times 3}{100} = 1,728$

So, the total interest = $1728

Now, Amount to be paid = Principal + Interest

⇒ A = $8000 + $1728 = $8728

Also, 1 year = 12 months

⇒ 3 years = 3 x 12 months = 36 months

So, total amount to be paid in 36 months is $8728.

⇒The amount to be paid in 1 month is $(\frac{8728}{36} ) = 242.44$

Hence, the monthly payment is $242.44 if loan is to paid off in 3 years.

3 0

3 years ago

PLEASE HELP!! I know I need to factor but I’m confused…

Veseljchak [2.6K]

Answer:

x = 16

Step-by-step explanation:

Given a tangent and a secant from an external point to a circle, then

The product of the external part and the whole of the secant is equal to the square of the tangent, that is

9(9 + x) = 15²

9(9 + x) = 225 ( divide both sides by 9 )

9 + x = 25 ( subtract 9 from both sides )

x = 16

5 0

3 years ago

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56 - (n + 4) For n = 44

loris [4]

Pretty sure the answer is 8

8 0

3 years ago

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Solve 12^x^2+5x-4 = 12^2x+6

faust18 [17]

The solutions for ‘x’ are 2 and -5

Step-by-step explanation:

Given equation:

$12^{x^{2}+5 x-4}=12^{2 x+6}$

Since the base on both sides as ‘12’ are the same, we can write it as

$x^{2}+5 x-4=2 x+6$

$x^{2}+5 x-2 x-4-6=0$

$x^{2}+3 x-10=0$

Often, the value of x is easiest to solve by $a x^{2}+b x+c=0$ by factoring a square factor, setting each factor to zero, and then isolating each factor. Whereas sometimes the equation is too awkward or doesn't matter at all, or you just don't feel like factoring.

The Quadratic Formula: For $a x^{2}+b x+c=0$ , the values of x which are the solutions of the equation are given by:

$x=\frac{-b \pm \sqrt{b^{2}-4 a c}}{2 a}$

Where, a = 1, b = 3 and c = -10

$x=\frac{-3 \pm \sqrt{(-3)^{2}-4(1)(-10)}}{2(1)}$

$x=\frac{-3 \pm \sqrt{9+40}}{2}$

$x=\frac{-3 \pm \sqrt{49}}{2}=\frac{-3 \pm 7}{2}$

So, the solutions for ‘x’ are

$x=\frac{-3+7}{2}=\frac{4}{2}=2$

$x=\frac{-3-7}{2}=\frac{-10}{2}=-5$

The solutions for ‘x’ are 2 and -5

6 0

3 years ago

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Solve for f. 2+1.25f=10-2.75f

Harrizon [31]

f = 2

Simplify both sides of the equation 1.25f+2=−2.75f+10

Add 2.75 to each side 4f+2=10

Subtract 2 from both sides 4f=8

Divide each side by 4 f=2

8 0

3 years ago

Read 2 more answers