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ivolga24 [154]
2 years ago
15

If , (4x + 3y) : (3x + 4y) = 24 : 25 , find the value of x : y .

Mathematics
2 answers:
Karo-lina-s [1.5K]2 years ago
8 0

<u>We </u><u>have </u><u>(</u><u> </u><u>4</u><u>x</u><u> </u><u>+</u><u> </u><u>3</u><u>y</u><u> </u><u>)</u><u> </u><u>:</u><u> </u><u>(</u><u> </u><u>3</u><u>x</u><u> </u><u>+</u><u> </u><u>4</u><u>y</u><u> </u><u>)</u><u> </u><u>=</u><u> </u><u>2</u><u>4</u><u> </u><u>:</u><u> </u><u>2</u><u>5</u><u> </u>

<u>\\ \sf\longmapsto \:  \frac{4x + 3y}{3x + 4y}  =  \frac{24}{25}</u>

<u>\\ \sf\longmapsto \: 25(4x + 3y) = 24(3x + 4y)</u>

<u>\\ \sf\longmapsto \: 100x + 75y = 72x + 96y</u>

<u>\\ \sf\longmapsto \: 100x - 72x = 96y - 75y</u>

<u>\\ \sf\longmapsto \: 28x = 21y</u>

<u>\\ \sf\longmapsto \:  \frac{x}{y}  =   \frac{21}{28}  =  \frac{3}{4}</u>

<u>Hence</u><u> </u><u>,</u><u> </u>

  • x : y = 3 : 4

Sindrei [870]2 years ago
3 0

\\ \sf\longmapsto \dfrac{4x+3y}{3x+4y}=\dfrac{24}{25}

  • Use cross multiplication

\\ \sf\longmapsto 24(3x+4y)=25(4x+3y)

\\ \sf\longmapsto 72x+96y=100x+75y

\\ \sf\longmapsto 96y-75y=100x-72x

\\ \sf\longmapsto 21y=28x

\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{21}{28}

  • Cut 7

\\ \sf\longmapsto \dfrac{x}{y}=\dfrac{3}{4}

\\ \sf\longmapsto x:y=3:4

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Hey, there!!

While simplifying the algebraic expression, you must be very careful about the signs.

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what two- dimensional shape is formed by a cross section of the cube shown if the cross section passes through the midpoints of
Nostrana [21]
<h2>Answer:</h2>

C= equilateral triangle

<h2>Step-by-step explanation:</h2>

To find this answer we need to know what a cube is. A cube is a prism whose sides all have the same length. It's something like the three dimensional version of a square. In the figure below, we have labeled each length of the cube as x. Also, the vertex we taken is in blue color, so we need to find each side length of the triangle. Since the cross section passes through the midpoints of three edges that intersect at the same vertices of the cube, then:

L_{1}=\sqrt{(\frac{x}{2})^2+(\frac{x}{2})^2} \\ \\ L_{1}=\sqrt{\frac{x^2}{4}+\frac{x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{2x^2}{4}} \\ \\ L_{1}=\sqrt{\frac{x^2}{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}} \\ \\ L_{1}=\frac{x}{\sqrt{2}}\frac{\sqrt{2}}{\sqrt{2}} \\ \\ L_{1}=\frac{\sqrt{2}x}{2}

Since this is a cube, then it is true that:

L_{1}=L_{2}=L_{3}=\frac{\sqrt{2}x}{2}

<em>Since the side lengths have the same value, this is an equilateral triangle.</em>

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