Answer:
A. finished 1km
Step-by-step explanation:
b. 8km per hour
Answer:
x=45
Step-by-step explanation:
30+15=45
Answer:
15.9%
Step-by-step explanation:
Percent decrease formula =
(Initial value - New value/Initial value) × 100
Initial value = 9200kg
New value = 7739.4kg
Percent decrease = (9200 - 7739.4/9200) × 100
Percent decrease = (1460.6/9200) × 100
Percent decrease = 15.8760869565%
Approximately = 15.9%
The percent of decrease in the amount of strawberries used annually is 15.9%
Answer:
Class Boundary = 1 between the sixth and seventh classes.
Step-by-step explanation:
Lengths (mm) Frequency
1. 140 - 143 1
2. 144 - 147 16
3. 148 - 151 71
4. 152 - 155 108
5. 156 - 159 83
6. 160 - 163 18
7. 164 - 167 3
The class boundary between two classes is the numerical value between the starting value of the higher class, which is 164 for the 7th class in this case, and the ending value of the class of the lower class, which is 163 for the 6th class in this case.
Therefore the class boundary between the sixth and seventh classes
= 164 - 163 = 1
Therefore Class Boundary = 1.
It can be seen that class boundary for the frequency distribution is 1.
If we take the difference between the lower limits of one class and the lower limit of the next class then we will get the class width value.
Therefore, Class width,
w = lower limit of second class - lower limit of first class
= 144 - 140
= 4
The question is simply asking us to create a word problem.
The word problem describing the division expression 3÷1/4 will be:
Given that Annie has 3 oranges and he wants to each orange into quarters, how many quarters will Annie have in total?