We have on the top of the figure one semircle, on the bottom of the figure another semicircle, to the left of the figure a line segment, and to the right of the figure another line segment, then we have a total of two semicircles and two line segments.
Answer: Fourth option: two semicircles and two line segments
Answer:
The variance of the measure of productivity = 141.67(to 2 d.p)
Step-by-step explanation:
The complete question and the step-by step explanation are contained in the files attached to this solution.
Answer:
The mean = 17.54
Step-by-step explanation:
Form a table as below;
<u>Interval Frequency{f} Midpoint of frequency{x} fx </u>
1-7 19 4 76
8-10 14 9 126
11-15 15 13 195
16-20 20 18 360
21-35 10 28 280
36-50 13 43 559
Sum 91 1596
The mean of grouped data = Sum of { Interval Midpoint * Frequency } /Sum of frequency
The mean= 1596 / 91
The mean = 17.54
Answer:
Step-by-step explanation:
1. A car requires 22 litres of petrol to travel a distance of 259.6 km
what is the distance that the car can travel on 63 ltr of petrol
22ltr = 259.6km
63ltr=
cross multiply
{63 x 259.6}/22 = 16354.8/22 = 743.4 km
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 63 ltr of petrol to travel 743.4km
2. To travel a distance of 2013.2 km
we would need to calculate the amount of fuel
A car requires 22 litres of petrol to travel a distance of 259.6 km
what amount of fuel would it require to travel 2013.2km
22ltr = 259.6km
xltr = 2013.2km
x is the value of petrol to cover 2013.2km
cross multiply
(2013.2 x 22)/259.6
44290.4/259.6 = 170.610169492≈170.6 ltr
A car requires 22 litres of petrol to travel a distance of 259.6 km, it would require 170.6 ltr of petrol to travel 2013.2km
if 1ltr is $1.99
170.6 ltr is (170.6 x 1.99)/1 = $339.494≈$339.5
The price of fuel consumed for 2013.2 km at 1 liter of petrol at $1.99 is $339.5
