Answer:
Yellow: 50
Red: 25
Step-by-step explanation:
5:10
5 times 5 = 25
10 times 5 = 50
Answer:
xy = 1
k = 79
Step-by-step explanation:
Question One
The first and third frames look to me to be the same. I'll treat them that way.
y = x^2 Equate y = x^2 to the result of 2y + 6 = 2x + 6
2y + 6 = 2(x + 3) Remove the brackets
2y + 6 = 2x + 6 Subtract 6 from both sides
2y = 2x Divide by 2
y = x
Now solve these two equations.
so x^2 = x
x > 0
1 solution is x = 0 from which y = 0. This won't work. x must be greater than 0. So the other is
x(x) = x Divide both sides by x
x = 1
y = x^2 Put x = 1 into x^2
y = 1^2 Solve
y = 1
The second solution is
(1,1)
xy = 1*1
xy = 1
Answer: A
Question Two
square root(k + 2) - x = 0
Subtract x from both sides
sqrt(k + 2) = x Square both sides
k + 2 = x^2 Let x = 9
k + 2 = 9^2 Square 9
k + 2 = 81
k = 81 - 2
k = 79
Answer:
The proportion of the population that is homozygous for the non-wiggling allele is 0.3056.
Step-by-step explanation:
Denote the variables as follows:
<em>q²</em> = number of people who are homozygous for the scalp-wiggling allele.
<em>p²</em> = number of people who are homozygous for the non-wiggling allele.
It is provided that the proportion of the population who are homozygous for the scalp-wiggling allele is, <em>q²</em> = 0.20.
Compute the value of <em>q</em> as follows:
Compute the value of <em>p</em> as follows:
Compute the proportion of the population who are homozygous for the non-wiggling allele as follows:
Thus, the proportion of the population that is homozygous for the non-wiggling allele is 0.3056.
Hello <u>156339</u>
Since we know the amount of money is always decreasing, then we should know to subtract by 35. Because 2.25 is the cost per meal and x is the number of meals, the total cost should be 2.25x, which is correct because y is the amount of money left over.
Our final equation would be:
<u><em>y = 35 - 2.25x</em></u>
:)
(1/12) / (1/3) = 1/x....now just solve it like a proportion.....oh, and x represents the number of hrs it would take to fill the whole tank
