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Natali [406]
2 years ago
5

Find a time where the hour and minute hand are 40 degrees apart.

Mathematics
1 answer:
sveta [45]2 years ago
6 0

Answer:

At 4:40, the minute hand is on the 8, and the hour hand is two-thirds of the way from the 4 to the 5

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You move down 5 units and up 5 units. You end at (1,3). Where did you start?
IgorC [24]

Answer:

(1, 3)

Step-by-step explanation:

Since up and down are opposites, the point didn't move at all.

I hope this helps!

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3 years ago
Imar got 8 Apples at the fair. His Sister Gave him 8 more how many apples does Imar Have altogether
Sunny_sXe [5.5K]

He has a total of 16 apples


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3 years ago
Read 2 more answers
What is 4x + 3 = 2x +7
VARVARA [1.3K]
Bring like terms together
(REMEMBER CHANGE THE SIGN WHEN MOVING ACROSS THE EQUAL SIGN i.e. - becomes + and + becomes -)
4x - 2x = 7 - 3
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divide both sides by 2
x = 2
4 0
4 years ago
Read 2 more answers
9x+3y-4z=37<br>4x+3y +7z =16<br>x-5y +8z=-31​
Evgen [1.6K]

Answer:

x = 2 , y = 5 , z = -1

Step-by-step explanation:

Solve the following system:

{9 x + 3 y - 4 z = 37 | (equation 1)

4 x + 3 y + 7 z = 16 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 4/9 × (equation 1) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+(5 y)/3 + (79 z)/9 = -4/9 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Multiply equation 2 by 9:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

x - 5 y + 8 z = -31 | (equation 3)

Subtract 1/9 × (equation 1) from equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - (16 y)/3 + (76 z)/9 = -316/9 | (equation 3)

Multiply equation 3 by 9/4:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x - 12 y + 19 z = -79 | (equation 3)

Add 4/5 × (equation 2) to equation 3:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+(411 z)/5 = -411/5 | (equation 3)

Multiply equation 3 by 5/411:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y + 79 z = -4 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 79 × (equation 3) from equation 2:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+15 y+0 z = 75 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 2 by 15:

{9 x + 3 y - 4 z = 37 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Subtract 3 × (equation 2) from equation 1:

{9 x + 0 y - 4 z = 22 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Add 4 × (equation 3) to equation 1:

{9 x+0 y+0 z = 18 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Divide equation 1 by 9:

{x+0 y+0 z = 2 | (equation 1)

0 x+y+0 z = 5 | (equation 2)

0 x+0 y+z = -1 | (equation 3)

Collect results:

Answer:  {x = 2 , y = 5 , z = -1

4 0
3 years ago
Use the distributive property 5(z+ 2) to rewrite this expression
Agata [3.3K]
You have to multiply everything inside the parentheses by 5.
So it will look like this
5z+10
6 0
3 years ago
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