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horsena [70]
3 years ago
8

You are playing a game where you flip 3 coins, if you get all tails you lose $15, for each heads you get $3. What is your expect

ed profit from this game?
Mathematics
1 answer:
UkoKoshka [18]3 years ago
6 0

Answer:

expected profit=$-3

Step-by-step explanation:

1 tail=-5

1 head=3

3/2=1.5

1.5*3=4.5

1.5*-5=-7.5

4.5-7.5=-3

$-3

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Answer:

5C1 (9C3) (5C3)

And replacing we got:

\frac{5!}{1! 4!} (\frac{9!}{3! (9-3)!}) (\frac{5!}{3! (5-3)!}) = 5*84*10=4200

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Step-by-step explanation:

For this case we can use the combinatory formula given by:

nCx= \frac{n!}{x! (n-x)!}

And for this case we have a total of 9 vegatables and 5 condiments and 5 types of tortilla. Then the total number of possibilities are:

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And replacing we got:

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Solve for x in the equation X2-8x+41 = 0 -
djverab [1.8K]

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

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Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

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