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posledela
3 years ago
15

Find the slope of the line.A -2B 2C -1/2D 1/2

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

I think is positive 2 I may be wrong.

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Given the equation y=12x, x representing number of hours worked, y representing amount of money earned, how much would John earn
JulijaS [17]

9514 1404 393

Answer:

  72

Step-by-step explanation:

Substitute 6 for x in the equation and do the arithmetic.

  y = 12x

  y = 12·6 = 72

John earns 72 money units in 6 hours.

8 0
3 years ago
Please help! Algebra 1 math.
olya-2409 [2.1K]
A.   The data in the table represent a function. y=x/2. This is seen as for every value of x in the table, y=x/2(half of it). You can show this further by trying this fact on each value.

B.   For the original function, when x =8, y=x/2=4
For the function given in this part, when x=8, y=3(8)-10
                                                                 y=24-10                                                                                                            y=14
     This means the relation given in this part has a greater value when x=8

C. When x=80, f(x)=3(80)-10
                           =240-10
                           =230 
4 0
3 years ago
Simplify the following expression .
Dafna11 [192]

Answer: 3m + 28

 ———————

    4  

8 0
2 years ago
Evaluate the sum of the finite geometric series.
Dmitry [639]

Answer:

descarga la aplicación photomath

4 0
3 years ago
A simple random sample of 60 items resulted in a sample mean of 80. The population standard deviation is σ = 15. a. Compute the
Kaylis [27]

Answer:

a) (76.21,83.79)

b) (77.32,82.68)    

c) Interval decreases    

Step-by-step explanation:

We are given the following information in the question:

Sample size, n = 60

Sample mean = 80

Sample standard Deviation, s = 15

a) 95% Confidence interval:

\mu \pm z_{critical}\frac{\sigma}{\sqrt{n}}

Putting the values, we get,

z_{critical}\text{ at}~\alpha_{0.05} = 1.96

80 \pm 1.96(\dfrac{15}{\sqrt{60}} ) = 80 \pm 3.79 = (76.21,83.79)

b) Sample size, n = 120

95% Confidence interval:

80 \pm 1.96(\dfrac{15}{\sqrt{120}} ) = 80 \pm 2.68 = (77.32,82.68)

c) As observed increasing the sample size, the confidence interval become smaller.

8 0
3 years ago
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