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posledela
3 years ago
15

Find the slope of the line.A -2B 2C -1/2D 1/2

Mathematics
1 answer:
Sindrei [870]3 years ago
8 0

I think is positive 2 I may be wrong.

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Help as soon as possible please
marta [7]

(3x + 5)° + (10x - 7)° = 180°

13x + (-2) = 180

13x = 180 + 2

13x = 182

x = 14

∠QRT = 3 * 14 + 5 = 42 + 5 = 47°

∠TRS = 10 * 14 - 7 = 140 - 7 = 133°

6 0
4 years ago
Before the 1936 US presidential election, a popular poll predicted that Alfred Landon would comfortably win against Franklin D.
Vinvika [58]

Answer:

wrong subject

Step-by-step explanation:

3 0
3 years ago
Makayla leaves a tip of $15. This was 15% of the bill before the tip.
Minchanka [31]

Answer:

100

Step-by-step explanation:

both the percentage and the money have the same number, and there's always 100% so it'd be 100 before the tip

8 0
3 years ago
Aaa help pls with this question
amm1812
It wont open it up, so no one can really help
7 0
3 years ago
There are two college entrance exams that are often taken by students, Exam A and Exam B. The composite score on Exam A is appro
elena55 [62]

Answer:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

Step-by-step explanation:

Problems of normally distributed samples can be solved using the z-score formula.

In a set with mean \mu and standard deviation \sigma, the zscore of a measure X is given by:

Z = \frac{X - \mu}{\sigma}

The Z-score measures how many standard deviations the measure is from the mean. After finding the Z-score, we look at the z-score table and find the p-value associated with this z-score. This p-value is the probability that the value of the measure is smaller than X, that is, the percentile of X. Subtracting 1 by the pvalue, we get the probability that the value of the measure is greater than X.

In this problem, we have that:

Two exams. The exam that you did score better is the one in which you had a higher zscore.

The composite score on Exam A is approximately normally distributed with mean 20.1 and standard deviation 5.1.

This means that \mu = 20.1, \sigma = 5.1.

You scored 24 on Exam A. So

Z = \frac{X - \mu}{\sigma}

Z = \frac{24 - 20.1}{5.1}

Z = 0.76

The composite score on Exam B is approximately normally distributed with mean 1031 and standard deviation 215.

This means that \mu = 1031, \sigma = 215.

You scored 1167 on Exam B, s:

Z = \frac{X - \mu}{\sigma}

Z = \frac{1167 - 1031}{215}

Z = 0.632

You had a better Z-score on exam A, so you did better on that exam.

The correct answer is:

B.The score on Exam A is better, because the percentile for the Exam A score is higher.

3 0
4 years ago
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