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Taya2010 [7]
3 years ago
7

Solve for x in the equation X2-8x+41 = 0 -

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

∴                  x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

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O It has the same slope and a different y-intercept.

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---

Data in the table:  slope is the rise (y) over the run (x) between two points (assuming the data represent a linear line).

 Change in x and y between two points.  I'll choose (-2/3,-3/4) and (1/3,-3/8).

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The slope of the equation is the same as the data in the table.

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To learn more on polygons: brainly.com/question/17756657

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