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Taya2010 [7]
3 years ago
7

Solve for x in the equation X2-8x+41 = 0 -

Mathematics
1 answer:
djverab [1.8K]3 years ago
7 0

Answer:

The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D  

Step-by-step explanation:

Given equation as :

x² - 8 x + 41 = 0

For quadratic equation  ax² + b x + c = 0

The value of x = \frac{-b\pm \sqrt{b^{2}-4\times a\times c}}{2\times a}

∴ For equation x² - 8 x + 41 = 0

Or,                x = \frac{8\pm \sqrt{-8^{2}-4\times 1\times 41}}{2\times 1}

Or,                x = \frac{8\pm \sqrt{-100}}{2}

Or,                x = \frac{8\pm 10i}{2}

∴                  x = ( 4 + 2 i ) , ( 4 - 2 i )

Hence The value of x fro the given equation is ( 4 + 2 i ) , ( 4 - 2 i )

I.e option D     Answer

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Answer:

x is less than or equal to negative 14.

Step-by-step explanation:

so for now we should pretend that the greater than or equal to is an equal sign, and simplify the problem to get x alone on a side

remove 5 from each side

-x/3=1/3-5

-x/3=14/3

multiply both sides by 3

-x=14

x=-14

so we can now replace the equal sign with the equal or greater to, so x is less than or equal to -14

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3 years ago
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givi [52]

Answer:

Step-by-step explanation:

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Which pattern has the fastest growth rate?
kotykmax [81]

▪▪▪▪▪▪▪▪▪▪▪▪▪  {\huge\mathfrak{Answer}}▪▪▪▪▪▪▪▪▪▪▪▪▪▪

The pattern having the fastest growth rate is :

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2 years ago
Find the area of the parallelogram with vertices:________.
marin [14]

Answer:

97.98

Step-by-step explanation:

The area of the parallelogram PQR is the magnitude of the cross product of any two adjacent sides. Using PQ and PS as the adjacent sides;

Area of the parallelogram = |PQ×PS|

PQ = Q-P and PS = S-P

Given P(0,0,0), Q(4,-5,3), R(4,-7,1), S(8,-12,4)

PQ = (4,-5,3) - (0,0,0)

PQ = (4,-5,3)

Also, PS = S-P

PS = (8,-12,4)-(0,0,0)

PS = (8,-12,4)

Taking the cross product of both vectors i.e PQ×PS

(4,5,-3)×(8,-12,4)

PQ×PS = (20-36)i - (16-(-24))j + (-48-40)k

PQ×PS = -16i - 40j -88k

|PQ×PS| = √(-16)²+(-40)²+(-88)²

|PQ×PS| = √256+1600+7744

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|PQ×PS| ≈ 97.98

Hence the area of the parallelogram is 97.98

3 0
3 years ago
(1+1/3)^2-2/9 <br> PLS HELPPPP MEEEE
Amiraneli [1.4K]

Answer:

14/9 or 1.555556

Step-by-step explanation:

1) Simplify 1 + 1/3 to 4/3.

(4/3)^2 - 2/9

2) Use Division Distributive Property: (x/y)^a = x^a/y^a.

4^2/3^2 - 2/9

3) Simplify 4^2 to 16.

16/3^2 - 2/9

4) Simplify 3^2 to 9.

16/9 - 2/9

5) Simplify.

14/9

(Decimal form: 1.555556)

Thanks, Eddie

8 0
1 year ago
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