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1 year ago

Help me guys and i will help u out

Mathematics

2 answers:

Furkat [3]1 year ago

6 0

Answer:

D) 7⅕b

Step-by-step explanation:

Just grab all of the b numbers and the regular numbers and do their own math

3/5b-2/5b=1/5b

7b+1/5b=7⅕b

-2+-12=-14

-14+14=0

0+7⅕b=7⅕b

Please give brainliest if I helped! :)

bearhunter [10]1 year ago

3 0

Answer:

Step-by-step explanation:

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If x-13 = k and k = 3, what is the value of x?

77julia77 [94]

Answer:

x = 16

16 - 13 = 3

***brainliest please

Step-by-step explanation:

5 0

2 years ago

FIND BD !!!!!!!!!!!!!!!!!!!!

Viktor [21]

BD = 2x-4

But it's also BE - CE + CD

BE is 3x-1

CE is 2x-3

CD is 2

BD = 3x-1 -(2x-3) +2

simplified

BD = 1x +4

since BD = BD (obviously), we can also say that the righthand sides of the two equation must be equal

2x -4 = 1x +4

let's solve for x and that put it into either of the 2 equations.

2x -4 = 1x +4

subtract 1x on both sides

x -4 = 4

add 4 on both sides

x = 8

substitute x for its value in 2x -4 = 1x +4

(this way we double check BD in two expressions at once. the equation should come out true, meaning same value for BD in each expression. both sides should be equal).

2*8 -4 = 1*8 +4

12 = 12

seems true

BD is safely 12

4 0

2 years ago

Use sigma notation to represent the sum of the first seven terms of the following sequence -4,-6,-8.....

lina2011 [118]

Answer:Answer:

$\sum\left {{7} \atop {1}} \right -n(3+n)$

Step-by-step explanation:

Given the sequence -4,-6,-8..., in order to get sigma notation to represent the sum of the first seven terms of the sequence, we need to first calculate the sum of the first seven terms of the sequence as shown;

The sum of an arithmetic series is expressed as $S_n = \frac{n}{2}[2a+(n-1)d]$

n is the number of terms

a is the first term of the sequence

d is the common difference

Given parameters

n = 7, a = -4 and d = -6-(-4) = -8-(-6) = -2

Required

Sum of the first seven terms of the sequence

$S_7 = \frac{7}{2}[2(-4)+(7-1)(-2)]\\\\S_7 = \frac{7}{2}[-8+(6)(-2)]\\\\S_7 = \frac{7}{2}[-8-12]\\\\\\S_7 = \frac{7}{2} * -20\\\\S_7 = -70$

The sum of the nth term of the sequence will be;

$S_n = \frac{n}{2}[2(-4)+(n-1)(-2)]\\\\S_n = \frac{n}{2}[-8+(-2n+2)]\\\\S_n = \frac{n}{2}[-6-2n]\\\\S_n = \frac{-6n}{2} - \frac{2n^2}{2}\\S_n = -3n-n^2\\\\S_n = -n(3+n)$

The sigma notation will be expressed as $\sum\left {{7} \atop {1}} \right -n(3+n)$ . The limit ranges from 1 to 7 since we are to find the sum of the first seven terms of the series.

3 0

2 years ago

Given the following equation, write a scenario that would lead to writing the equation. 2r + 15 = 25

tangare [24]

Answer:

the third/yellow one

Step-by-step explanation:

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2 years ago

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3x+y=8, 2x+4y=12 (system of equations)

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