If <em>x</em> = 4.338338338…, then
1000<em>x</em> = 4338.338338338…
and subtracting <em>x</em> from this eliminate the trailing decimal.
1000<em>x</em> - <em>x</em> = 4338.338338338… - 4.338338338…
999<em>x</em> = 4334
<em>x</em> = 4334/999
Answer:
A man borrows * 8000
He agrees to repay with a total interest of 1360 in 12 monthly instalments.
Each instalment being less than the preceding one by * 40
= x 40
= 12 x 34
= 408 (Ans)
A: 3.2/294=12/T
<span>T=1102.5 K </span>
<span>*** </span>
<span>*** </span>
<span>b: V/T => V/1088 = 4000/294 </span>
<span>V = 14802.7 L = 14.8 m^3 </span>
<span>*** </span>
<span>*** </span>
<span>c. </span>
<span>pV/T </span>
<span>1.1*V/294 = 12*15000/1088 </span>
<span>V= 48.64 m^3</span>
Answer:
1) For each value of x, a value of y is increased by 5.
x = 0, y = 5
x = 1, y = 10
x = 2, y = 15
x = 3, y = 20
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2) For each two values of x, a value of y is increased by 10.
x = 0, y = -2
x = 2, y = 8
x = 4, y = 18
x = 6, y = 28
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3)
x = 0, y = 1
x = 1, y =
x = 5, y = 3
x = 10, y = 5
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4)
x = 0, y = 2
x = 1, y = 17
x = 2, y = 32
x = 5, y = 77
Step-by-step explanation:
This is as easy as replacing x for the actual value show on the table.
1)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 3, y = ?
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2)
When x = 0, y = ?
When x = 2, y = ?
When x = 4, y = ?
When x = 6, y = ?
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3)
When x = 0, y = ?
When x = 1, y = ?
When x = 5, y = ?
When x = 10, y = ?
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4)
When x = 0, y = ?
When x = 1, y = ?
When x = 2, y = ?
When x = 5, y = ?
Given:
Consider the below figure attached with this question.
To find:
The perimeter of the polygon UVWXYZ.
Solution:
All sides and vertical and horizontal. So, we can easily find the side lengths of the given polygon by counting the boxes between two points.
From the figure it is clear that,
UV = 9 units
VW = 2 units
WX = 3 units
XY = 3 units
YZ = 6 units
ZU = 5 units
Now, perimeter is the sum of all the sides.
Therefore, the perimeter of UVWXYZ is 28 units.