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alisha [4.7K]
3 years ago
8

Find the value of x.

Mathematics
1 answer:
suter [353]3 years ago
3 0

Answer:

104 degrees

Step-by-step explanation:

71 degrees is one corner

Opposite corner is equal

Middle angle: 180-71-71 = 38

isosceles triangle bottom angle = 38 and 38

top angle = 180 - 38 - 38 = 104 degrees

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Which number should.be added to the data so that the range of the data is 31? 54,72,64,57
Sergio039 [100]

Answer:  41 or 85

<u>Step-by-step explanation:</u>

Range is the difference between the largest number and the smallest number.

The largest number is 72.  72 - 31 = 41

The smallest number is 54.  54 + 31 = 85

Adding either ONE of those numbers will result in a range of 31.

3 0
3 years ago
At the beginning of an experiment, the number of bacteria in a colony was counted at time t=O. The number of bacteria in the col
yan [13]

Answer:

1092

Step-by-step explanation:

We have been given that the number of bacteria in the colony t minutes after the initial count modeled by the function B(t)=9(3)^t. We are asked to find the average rate of change in the number of bacteria over the first 6 minutes of the experiment.

We will use average rate of change formula to solve our given problem.

\text{Average rate of change}=\frac{f(b)-f(a)}{b-a}

Upon substituting our given values, we will get:

\text{Average rate of change}=\frac{b(6)-b(0)}{6-0}

\text{Average rate of change}=\frac{9(3)^6-9(3)^0}{6}

\text{Average rate of change}=\frac{9(729)-9(1)}{6}

\text{Average rate of change}=\frac{6561-9}{6}

\text{Average rate of change}=\frac{6552}{6}

\text{Average rate of change}=1092

Therefore, the average rate of change in the number of bacteria is 1092 bacteria per minute.

8 0
3 years ago
Solve (3x-4)-(5x-3) and simplify the answer!
AnnyKZ [126]

Answer:

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Step-by-step explanation:

(3x-4)-(5x-3)

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Combine like terms

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7 0
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disa [49]

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5 0
3 years ago
6-6*4+3=? answer please ​
Neporo4naja [7]

Answer:

-15

Step-by-step explanation:

Using the BODMAS ORDER..

6-6*4+3= 6 - 24 + 3 = 9 -24 = - 15

7 0
3 years ago
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