The ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
<u>Explanation:</u>
We need to find the time at which the ball will be at height 19 feet.
Equation:
h = 3 + 34t - 16t²
19 = 3 + 34t - 16t²
16 = -16t² + 34t
-16t² + 34t - 16 = 0
On solving the equation, we get
t1 = 0.7 s and t2 = 1.42s
Therefore, the ball will be at height 19 feet first at 0.7 sec and then at 1.42 sec.
Answer:f in the chat
Step-by-step explanation:
Answer: 70
Step-by-step explanation:
a^2 + b^2 = c^2
24^2 + b^2 = 74^2
576 + b^2 = 5,476
-576 -576
b^2 =4,900
(square root)
b =70
I'm not sure... I think it is 60 because 2*3=6 and 9*6=54 and when you add them together you get 60.
3(x - 1) = 2x + 9
3x - 3 = 2x + 9
3x (-2x) -3 (+3) = 2x (-2x) + 9 (+9)
(3x -2x) = (9 + 9)
(x) = (18)
x = 18
x = 18 is your answer
hope this helps
