Answer:
BD does bisect the angle created by ABC, however it does not bisect segment AC. So it really depends on what you are determining the bisection to be.
Step-by-step explanation:
We can tell that it is bisecting the angle since it creates two congruent angles.
We can tell that it does not bisect the segment as AD and CD are not the same length.
Answer:
b.
Step-by-step explanation:
We have to look at sign changes in f(x) to determine the possible positive real roots.

There is only one sign change here, between the -8x and the +4. So that means there is only 1 possible real positive root.
Now we have to look at sign changes in f(-x) to determine the possible negative real roots.

There are 3 sign changes here. That means there are either 3 negative roots or 3-2 = 1 negative root. So we have:
1 positive
3 or 1 negative
We need to pair them up now with all the possible combinations.
If we have 1 positive and 1 negative, we have to have 2 imaginary
If we have 1 positive and 3 negative, we have to have 0 imaginary
Keep in mind that the total number or roots--positive, negative, imaginary--have to add up to equal the degree of the polynomial. This is a 4th degree polynomial, so we will have 4 roots.
<em>8gh x 2g2 x 3h</em>
<em>Simplified is 8 · 3 gghhxx ·2 · 2 </em>
<em>and can also be:</em>
<em>8ghx · 2g · 2x · 3h </em>
<em>24g ₁ ₊ ₁ h ₁ ₊ ₁ x ₁ ₊ ₁ · 2 ₁ ₊ ₁</em>