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Vera_Pavlovna [14]
2 years ago
6

A youth group earns $600 for charity and decides to put it in a bank. Calculate the amount of money the group will have for each

scenario.
Part A chase bank pays simple interest at 5% and the group leaves the money for 5 years
part B witney bank pays an interest rate of 4% compounded annually and the group leaves the money for 6 years
Mathematics
1 answer:
igomit [66]2 years ago
4 0

Based on the types of compounding and the interest rates, the following are true:

  • Part A - The group will have $750
  • Part B - The group will have $759.19

When using simple interest, the amount the group will have is:

<em>= Amount x ( 1 + rate x number of years )</em>

= 600 x ( 1 + 5% x 5)

= $750

When using compound interest, the group will have:

<em>= Amount x ( 1 + rate) ^ Number of years</em>

= 600 x ( 1 + 4%)⁶

= $759.19

In conclusion, compound interest yields more.

<em>Find out more about </em><em>compound interest </em><em>at brainly.com/question/25263325. </em>

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LUCKY_DIMON [66]

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so f(x) = g(x) at those points, so let's take the integral of the top - bottom functions for both intervals, namely f(x) - g(x) from -2 to 0 and g(x) - f(x) from 0 to +2.

\stackrel{f(x)}{2x^3-x^2-5x}~~ - ~~[\stackrel{g(x)}{-x^2+3x}]\implies 2x^3-x^2-5x+x^2-3x \\\\\\ 2x^3-8x\implies 2(x^3-4x)\implies \displaystyle 2\int\limits_{-2}^{0} (x^3-4x)dx \implies 2\left[ \cfrac{x^4}{4}-2x^2 \right]_{-2}^{0}\implies \boxed{8} \\\\[-0.35em] ~\dotfill

\stackrel{g(x)}{-x^2+3x}~~ - ~~[\stackrel{f(x)}{2x^3-x^2-5x}]\implies -x^2+3x-2x^3+x^2+5x \\\\\\ -2x^3+8x\implies 2(-x^3+4x) \\\\\\ \displaystyle 2\int\limits_{0}^{2} (-x^3+4x)dx \implies 2\left[ -\cfrac{x^4}{4}+2x^2 \right]_{0}^{2}\implies \boxed{8} ~\hfill \boxed{\stackrel{\textit{total area}}{8~~ + ~~8~~ = ~~16}}

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2 years ago
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Answer:

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Step-by-step explanation:

u didn't said the numbers but here is the explanation

6÷2=3

6÷3=2

12÷3=4

12÷2=6

18÷2=9

18÷3=6

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