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WITCHER [35]
3 years ago
14

The length of the rectangle is 9 inches. The area is 72 square inches. What is the width of the rectangle?

Mathematics
1 answer:
mote1985 [20]3 years ago
4 0

Answer:

8

Step-by-step explanation:

Formula for area = Length times width

72 divided by 9 = 8

Double check: 9(length) x 8 (width) = 72 (area).

Width = 8 inches

Hope this helped! If it did, please give brainliest! :)

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Three ounces of cinnamon cost $2.40. If there are 16 ounces in 1 pound, how much does cinnamon cost per pound?
Veseljchak [2.6K]

Answer:

80¢\lb.; 58 667\1000 ft.\sec.

Step-by-step explanation:

Divide the cost by three; multiply 40 by 1.466675.

7 0
3 years ago
X^2-16/x^2-3x-4 simply
kolbaska11 [484]

Answer:

x+4/x+1

Step-by-step explanation:

hope this can help you :)

7 0
3 years ago
Read 2 more answers
a teacher promised a movie day to the class that did better, on average, on their test. The box plot shows the results of the te
natka813 [3]

The question is incomplete. The complete question is

A teacher promised a movie day to the class that did better, on average, on their test. The box plot shown in the below-mentioned figure shows the results of the test.

Which class should get the reward, and why?

- The 2nd-period class should get the reward. They have the highest score, a perfect 100.

- The 2nd-period class should get the reward. They have a higher median.

- The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

- The 4th-period class should get the reward. Their lowest score is an outlier and should be thrown out.

The box plot shown in the question provides the information that
In 2nd period the minimum of the data is 77, first quartile is 78, median of the data is 89, third quartile is 92 and the maximum of the data is 100.
Hence, the mean of the results of 2nd period is

\frac{77+78+89+92+100}{5}=87.2

In 2nd period the minimum of the data is 72, first quartile is 83, median of the data is 89, third quartile is 96 and the maximum of the data is 98.

Hence, the mean of the results of the 4th period is

\frac{72+83+89+96+98}{5}=87.6

Hence, obviously, the 4th period is having more mean.

Moreover, we can observe that if more of the marks are on the higher side the average will automatically be more. Hence, as the first and the third quartiles are more on the 4th-period, so the average marks for the 4th period must be better.

So, just by observing the box plot, we can give the statement that  "The 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class. "

Therefore, the 4th-period class should get the reward. Though the medians are the same, the first and third quartiles are higher, so the students did better on average than in the 2nd-period class.

Learn more about box plots here-

brainly.com/question/1523909

#SPJ10

6 0
2 years ago
There are 60 seats on a train. 6 of the seats are empty. What percentage of the seats on the train are empty?
sergij07 [2.7K]

Answer:

10%

Step-by-step explanation:

  1. Set up a proportion: \frac{6}{60} = \frac{x}{100}  
  2. Cross multiply, then divide: 6 × 100 = 600, 600 ÷ 60 = 10
  3. 10/100 = 10%

I hope this helps!

6 0
3 years ago
-635 simplest radical form
zhenek [66]

Answer:

I believe it is (Square root) And then make it positive. Therefore, 634 should be the correct answer.

Step-by-step explanation:

7 0
3 years ago
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