All categories

3 years ago

The length of the rectangle is 9 inches. The area is 72 square inches. What is the width of the rectangle?

Mathematics

1 answer:

mote1985 [20]3 years ago

4 0

Answer:

Step-by-step explanation:

Formula for area = Length times width

72 divided by 9 = 8

Double check: 9(length) x 8 (width) = 72 (area).

Width = 8 inches

Hope this helped! If it did, please give brainliest! :)

You might be interested in

15 POINTS-

Doss [256]

I think it’s $3.55
I think this because if u subtract 2.45- 45% = 1.10 sooo u will have to add $1.10 to 2.25 and that will add up the 45% that Walmart is paying with the original price.

8 0

2 years ago

Please help me asap!!

Amiraneli [1.4K]

Answer:

Step-by-step explanation:

6 0

3 years ago

In basketball, hang time is the time that both of your feet are off the ground during a jump. The equation for hang time is t =

const2013 [10]

Considering the hang time equation, it is found that Player 1 jumped 0.68 feet higher than Player 2.

<h3>What is the hang time equation?</h3>

The hang-time of the ball for a player of jump h is given by:

$t = 2\left(\frac{2h}{32}\right)^{\frac{1}{2}}$

The expression can be simplified as:

$t = 2\sqrt{\frac{h}{16}}$

For a player that has a hang time of 0.9s, the jump is found as follows:

$0.9 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.9}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.9}{2}\right)^2$

$h = 16\left(\frac{0.9}{2}\right)^2$

h = 3.24 feet.

For a player that has a hang time of 0.8s, the jump is found as follows:

$0.8 = 2\sqrt{\frac{h}{16}}$

$\sqrt{\frac{h}{16}} = \frac{0.8}{2}$

$(\sqrt{\frac{h}{16}})^2 = \left(\frac{0.8}{2}\right)^2$

$h = 16\left(\frac{0.8}{2}\right)^2$

h = 2.56 feet.

The difference is given by:

3.24 - 2.56 = 0.68 feet.

More can be learned about equations at brainly.com/question/25537936

#SPJ1

3 0

1 year ago

Part A: If (72)x = 1, what is the value of x? Explain your answer. (5 points)

vichka [17]

Answer:

see below

Step-by-step explanation:

Part A: (72)^x = 1

Take the log base 72 of each side

log72(72^x) = log 72(1)

We know log a^b = b log a

x log72(72) = log72(1)

x = log72(1)

x = 0

Part A: (70)^x = 1

Take the log base 70 of each side

log70(70^x) = log70(1)

We know log a^b = b log a

x log70(70) = log70(1)

x = log70(1)

x = 0

7 0

3 years ago

What is the constant in this algebraic expression? 7d+2 I need help

snow_lady [41]

It is 2 because no variable

6 0

3 years ago