for the first 18 days of the month, buffet dinner generate $11,800 in sales. The buffet sale target for the month is $18,650. Gi
1 answer:
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Answer:
The expected number of appearance defects in a new car = 0.64
standard deviation = 0.93(approximately)
Step-by-step explanation:
Given -
7% had exactly three, 11% exactly two, and 21% only one defect in cars.
Let X be no of defects in a car
P(X=3) = .07 , P(X=2) = .11 , P(X=3) = .21
P(X=0 ) = 1 - .07 - .11 - .21 = 0.61
The expected number of appearance defects in a new car =
E(X) = =
= 0.64
= variation of E(X) =
=
= = 0.8704
standard deviation = =
= 0.93(approximately)
Answer:
a) 0.172
b) 0.167
c) 0.1404
Step-by-step explanation:
Margin of error, E =
here,
p = probability of the event
n = sample size
a) n = 30
p = 10 ÷ 30 = 0.333
Therefore,
E =
= 2 × 0.0861
= 0.172
b) n = 30
p = 21 ÷ 30 = 0.7
Therefore,
E =
= 2 × 0.0836
= 0.167
c) n = 30
p = 22 ÷ 50 = 0.44
Therefore,
E =
= 2 × 0.0702
= 0.1404