
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
So, we have the following equation...

Remember
and
is the following...

Therefore, 
So, your final answer is
.
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<em>Glad to help!</em>

(If It's a number like this: 8/9 then it's a fraction)
Answer:
<h2><em><u>
9. -2/6</u></em></h2><h2><em><u>
10. -6/-10</u></em></h2><h2><em><u>
11. 3/4</u></em></h2>
Step-by-step explanation:
Yay, I love doing these!
9.} 6 - 8 and 4- -2= -2/6
10.} 3 - 9 and -1 - 9= -6/-10
11.} -1 - -7 and 5 - -3= 6/8 simplify it by 2= 3/4
Answer:

Step-by-step explanation:
Given
-- of the roadworks

Required
Determine the speed
In this case:


<em></em>
<em> --- approximated</em>
Answer:
Do you have a picture?
Step-by-step explanation: