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snow_tiger [21]
3 years ago
6

For art class, you need to make a scale drawing of the Parthenon using the scale 1 in. = 5 ft. The Parthenon is 228 ft long.

Mathematics
1 answer:
aleksandr82 [10.1K]3 years ago
7 0

Answer:

228/5= 45.6 inches, rounded is <em><u>46 inches</u></em>

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Solve the inequality
guajiro [1.7K]

Answer:

c > 9

Step-by-step explanation:

\dfrac{2c}{3}+1 > 7

Subtract 1 from both sides:

\implies \dfrac{2c}{3} > 6

Multiply both sides by 3:

\implies 2c > 18

Divide both sides by 2:

\implies c > 9

7 0
3 years ago
Read 2 more answers
7. What is the solution to x2 + 10x + 27 = 0 when written in the form a ± bi? (1 point)
son4ous [18]

Answer:

<u>The correct answer is D. -5 +/- i√2</u>

Step-by-step explanation:

Let's solve for x, the equation given to us, this way, using the quadratic formula:

x = (- b +/- √b² - 4ac)/2a

Replacing with the real values, we have:

x = (-10 +/- √10² - 4 * 1 * 27)/2

x = (-10 +/- √100 -108)/2

x = (-10 +/- √-8)/2

x = (-10 +/- √-1 * 4 * 2)/2 Let's recall that √-1 = i

x = (-10 +/- 2i√2)/2

x = 2 (-5 +/- i√2)/2 (Dividing by 2 both the numerator and the denominator)

<u>x₁ = -5 + i√2</u>

<u>x₂ = -5 - i√2</u>

<u>The correct answer is D. -5 +/- i√2</u>

7 0
4 years ago
Read 2 more answers
20 POINT PLEASE QUICKLY
sdas [7]

Answer: the ordered pair is (-14,-6)

Step by step:

x – 2y = -2    (Eq. 1)

x – 4y = 10   (Eq. 2)

Isolate x in Eq. 2:

x = -2 + 2y

Substitute that solution x in Eq. 2:

x - 4y = 10

-2 + 2y - 4y = 10

Solve for y:

-2 - 2y = 10

-2y = 10 + 2 = 12

y = -6

Then calculate value for x using the above value for y

x = -2 + 2y

x = -2 + 2(-6) = -14

The solution is (x,y)=(-14,-6)    

5 0
3 years ago
Simplify 3 x n x p x 6
Natali5045456 [20]

Answer:

18np

Step-by-step explanation:

3 × n × p × 6

18 × n × p

18n × p

18np

<h2 /><h2 /><h2 /><h2>please follow me</h2>
5 0
3 years ago
Simplify the expression and solve the equation. Show all calculations
melamori03 [73]

 

\displaystyle\bf\\\sqrt{5p+5}=\sqrt{6p+3}\\\\ 5p+5=6p+3\\\\5p-6p=3-5\\\\-p=-2~\Big|\times(-1)\\\\\boxed{\bf p=2}\\\\\text{Verify:}\\\\\sqrt{5\times2+5}=\sqrt{6\times2+3}\\\\\sqrt{10+5}=\sqrt{12+3}\\\\\sqrt{15}=\sqrt{15}~~~~OK!

.

4 0
4 years ago
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