Answer:
4 in 2,417
4 in 2,147
Step-by-step explanation:
the place value of 4 in 2,417 is HUNDREDS
while the place value of 4 in 2,147 is TENS
Therefore the place value of 4 in 2,417 is ten times the value of 4 in 2,147
33)
(5x²+3)+(15x²+2)
5x^2+15x^2+3+2
20x^2+5
5(4x^2+1)
39)
(14h^4+3h^3)-(9h^4+2h^3)
14h^4-9h^4+3h^3-2h^3
5h^4+h^3
h^3(5h+1)
Using the normal distribution, it is found that 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
<h3>Normal Probability Distribution</h3>
The z-score of a measure X of a normally distributed variable with mean
and standard deviation
is given by:

- The z-score measures how many standard deviations the measure is above or below the mean.
- Looking at the z-score table, the p-value associated with this z-score is found, which is the percentile of X.
The mean and the standard deviation are given, respectively, by:

The proportion of full term newborn female infants with a head circumference between 31 cm and 36 cm is the <u>p-value of Z when X = 36 subtracted by the p-value of Z when X = 31</u>, hence:
X = 36:


Z = 1.83
Z = 1.83 has a p-value of 0.9664.
X = 31:


Z = -2.33
Z = -2.33 has a p-value of 0.0099.
0.9664 - 0.0099 = 0.9565.
0.9565 = 95.65% of full term newborn female infants with a head circumference between 31 cm and 36 cm.
More can be learned about the normal distribution at brainly.com/question/24537145
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Answer:
5398
Step-by-step explanation:
7715-2212+10-(5x23)
7715-2212+10-115
5503+10-115
5513-115
5398