Sin^-1(1/2) Please help I don't know how to do inverse or arcs Thanks
2 answers:
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Answer:
vertical asymptote at x=-1
horizontal asymptote at y=0
Step-by-step explanation:
To find vertical asymptote we set the denominator =0 and solve for x
x+1=0 (subtract 1 from both sides)
x=-1
So, vertical asymptote at x=-1
To find horizontal asymptote we look at the degree of both numerator and denominator
there is no variable at the numerator , so degree of numerator =0
degree of denominator =1
When the degree of numerator is less than the degree of denominator
then horizontal asymptote at y=0