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torisob [31]
2 years ago
15

Both copy machines reduce the dimensions of images that are run through the machines. Which statement is true about the results

of using these copiers?
As the number of copies increases, the dimensions of the images continue to decrease until reaching 0.
As the number of copies increases, the dimensions of the images continue to increase toward, but never reach, positive infinity.
As the number of copies increases, the dimensions of the images continue to decrease toward, but never reach, 0.
As the number of copies increases, the dimensions of the images continue to increase until reaching 8.
Mathematics
2 answers:
anzhelika [568]2 years ago
7 0

Answer:

As the number of copies increases, the dimensions of the images continue to decrease toward, but never reach, 0.

Step-by-step explanation:

myrzilka [38]2 years ago
5 0

Answer:

Give me a few minutes and ill put the answer in

Step-by-step explanation:

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Define table represents a group frequency discretion of the number of hours spent on the computer per week for 49 student. What
Scilla [17]

Observe the given data distribution table carefully.

The 5th class interval is given as,

14.0-17.4

The upper limit (UL) and lower limit (LL) of this interval are,

\begin{gathered} UL=17.4 \\ LL=14.0 \end{gathered}

Thus, the upper-class limit of this 5th class is 17.4.

6 0
1 year ago
1. A certain ceiling is made up of tiles. Every square meter of ceiling requires 10.75 tiles. Fill in the table with the missing
dybincka [34]

Given:

Consider the below table attached with this question.

Every square meter of ceiling requires 10.75 tiles.

To find:

The missing values in the table.

Solution:

We have,

1 square meter of ceiling =  10.75 tiles.      ...(i)

Therefore, the number of tiles corresponding to 1 square meter of ceiling is 10.75.

Multiply both sides by 10.

10×1 square meter of ceiling =  10×10.75 tiles.

10 square meter of ceiling =  107.5 tiles.

Therefore, the number of tiles corresponding to 10 square meter of ceiling is 107.5.

Divide both sides by 10.75 in (i).

\dfrac{1}{10.75} square meter of ceiling = 1 tile.

Multiply both sides by 100.

\dfrac{100}{10.75} square meter of ceiling = 100 tiles.

On approximating the value, we get

9.3 square meter of ceiling = 100 tiles.

Therefore, the square meters of ceiling corresponding to 100 tiles is about 9.3.

Multiply both sides by a in (i).

a×1 square meter of ceiling =  a×10.75 tiles.

a square meter of ceiling =  10.75a tiles.

Therefore, the number of tiles corresponding to a square meter of ceiling is 10.75a.

8 0
3 years ago
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How many calcium ions are in 0.5 mol of CaCl2?
slamgirl [31]
1 Calcium  ion / formula unit times  0.5 moles CaCl2 x 6.02 x 10^23 = 

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3 0
3 years ago
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If x = 10, which lines are parallel? Check all that apply.
natita [175]

Answer:

b||c; c||d; b||d

Step-by-step explanation:

Substituting 10 for x, in the angle beside b we have

7(10)-5 = 70-5 = 65

In the angle beside c we have

10(10)+15 = 100+15 = 115

In the angle beside d we have

12(10)-5 = 120-5 = 115

In the angle beside we have

8(10)-25 = 80-25 = 55

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The angle beside c and the angle beside d would be alternate interior angles; this is because they are inside the block of lines made by c and d and on opposite sides of the transversal.  These two angles are congruent; this means that c||d.

Since b||c and c||d, by the transitive property, b||d.

4 0
3 years ago
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Will report anybody who gives a link!<br><br> 3,947 ÷ 45 = (?) R (?)
Free_Kalibri [48]

Answer:

87.7(1)

=

87 Remainder 32

8 0
3 years ago
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