Answer:
Question 1: 4.5(10^−7)(2(10^4))
=
9/1000
(Decimal: 0.009)
Question 2:
mass of neutron/mass of electron = 2*10-24/(9*10-28)
2x10^(-24)/9x10^(-28)
d is closest.
Question 3:
4(10^3)(12(10^5))
=4000*1200000
=4*1000*12*100000
=(4*12)*(1000*100000)
=48*100000000
=4800000000
And these things : ^ mean raising the number to become exponets and when I put the number into a bold text thats the answer!
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Answer:
See explanation
Step-by-step explanation:
<u> ASA Postulate (Angle-Side-Angle):</u>
If two angles and the included side of one triangle are congruent to the corresponding parts of another triangle, then the triangles are congruent.
Consider triangles XYB and ZYA. In these triangles
- ∠X≅∠Z (given)
- XY≅ZY (given)
- ∠Y is common angle
By ASA Postulate, triangles XYB and ZYA are congruent. Congruent triangles have congruent corresponding sides, so
BX≅AZ
Answer:
Sally has been measuring the tree for 4 months
Step-by-step explanation:
The correct question is as follows;
Sally has been measuring the tree in her yard for a science project. The tree has grown 1/2 of an inch each month and grown a total of 2 inches taller. How many months has Sally been measuring this tree?
.........................................................................................
Solution;
The tree has grown 1/2 of an inch each month and has grown a total of 2 inch taller.
We now need to know the number of months in which the measuring has been taking place.
To know the number of months, we simply need to divide the change in height which is 2 inch by the individual month growth rate which is 1/2 inch
So mathematically, that would be 2/1/2 = 2 * 2 = 4 months
We are given two binomials: x+4 , x^2-9.
x+4 can't be factored. Therefore, it is a prime.
Let us work on x^2-9.
9 could be written as 3^2.
Therefore, x^2-9 = x^2 - 3^2.
Now, we can apply difference of the squares formula to factor it.
We know a^2 -b^2 = (a-b) (a+b).
Therefore, x^2 - 3^2 can be factored as (x-3) (x+3).
So, x^2-9 is not a prime binomial because it can be factored as (x-3) (x+3).
