Answer:
0.27
Step-by-step explanation:
To solve this problem, we will use Set Theory Approach to Probability.
Let U = the Sample Space which consists of all possible tests.
Of course U = {1,2,3 .... ,30}
So, no elements in that.
U = n = 30
Let Q = the event bearing a multiple of 4 No winning ticket, and,
R = the case that has the No. 19 winning ticket
∴
Q = { 4, 8, 12 , 16 , 20, 24 , 28} , and
R = {19} , so that
Q ∩ R = ϕ
P(Q ∩R ) = 0
As, n(Q) = 7 , n(R) = 1 , we have,
P (Q) = =
, and P (R) =
P
(Q∪R) = P(Q
) + P(R) − P(A∩B) = +
− 0 =
≅ 0.27 .
