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gizmo_the_mogwai [7]
3 years ago
12

In a four-pulley system, 1200N load is raised by applying 400N effort. Calculate M.A, V.R and efficiency of pulley system.​

Physics
1 answer:
ziro4ka [17]3 years ago
8 0

The M.A, V.R and the efficiency of the pulley system are 3, 4 and 75 % respectively

The Mechanical Advantage (M.A) of the pulley can be calculated using the formula below.

<h3> Formula:</h3>
  • M.A = Load(L)/Effort(E)............. Equation 1

From the question,

<h3>Given:</h3>
  • L = 1200 N
  • E = 400 N

Substitute into equation 1

  • M.A = 1200/400
  • M.A = 3.

For The V.R,

The number of pulley systems is equal to the Velocity ratio of the pulley.

Therefore,

V.R = 4

<h3>Efficiency:</h3><h3>Formula:</h3>
  • E(%) = (M.A/V.R)100.............. Equation 2

Substitute the values into equation 2

  • E(%) = (3/4)100
  • E(%) = 75 %

Hence, The M.A, V.R and the efficiency of the pulley system are 3, 4 and 75 % respectively

Learn more  about pulley here: brainly.com/question/177456

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2 1100 kg cars drive east; the first moving at 30 m/s the 2nd at 15 m/s what is the magnitude of the total momentum of the syste
11Alexandr11 [23.1K]
<h3>Answer:</h3>

49500 kgm/s

<h3>Explanation:</h3>

Data given;

  • First car; Mass = 1100 kg
  • Velocity = 30 m/s
  • Second car; mass = 1100 kg
  • Velocity = 15 m/s

We are required to calculate the total momentum of the system.

  • We need to know that momentum is calculated by multiplying the velocity of a body by its mass.
  • Therefore;

Momentum of the first car = 1100 kg × 30 m/s

                                           = 33,000 kgm/s

Momentum of the second car = 1100 kg × 15 m/s

                                                  = 16,500 kgm/s

Therefore;

Total momentum = 33,000 kgm/s + 16,500 kgm/s

                             = 49500 kgm/s

Thus, the total momentum of the system is 49500 kgm/s

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The picture shows three sets of balloons, all with a particular charge. Which of the picture(s) is true? Please explain.
devlian [24]
<span>Letter C has the correct illustration. Two objects with the same charge (in this case, both are positively charged) will repel each other. </span>  

Letter A is incorrect because a positive charged object will attract a negatively charged object.  

Letter B is incorrect because both of them are negatively charged, which means they should be repelling each other.
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Occasionally, people can survive falling large distances if the surface they land on is soft enough. During a traverse of Eiger'
uranmaximum [27]

Answer:

4611.58 ft/s²

Explanation:

t = Time taken

u = Initial velocity

v = Final velocity

s = Displacement

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Equation of motion

v^2-u^2=2as\\\Rightarrow v=\sqrt{2as+u^2}\\\Rightarrow v=\sqrt{2\times 32.174\times 516+0^2}\\\Rightarrow v=182.218\ ft/s

v^2-u^2=2as\\\Rightarrow a=\frac{v^2-u^2}{2s}\\\Rightarrow a=\frac{0^2-182.218^2}{2\times 3.6}\\\Rightarrow a=-4611.58\ ft/s^2

Magnitude of acceleration while stopping is 4611.58 ft/s²

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