A lot of the biology particles can be certified by a sphychiatrist that can determine weather they are infected with Ebola
A charged particle has an electrostatic field surrounding it.
When the particle is in motion, the moving charge is an
electric current, and that has a magnetic field around it.
Answer:
The ocean waves is a mechanical wave that transmits mechanical energy in the wave by the synchronized and repeated oscillation of the waters about an equilibrium level such that as the wave approaches the shoreline, and the water depth decreases, the height of the wave also increases reflecting the effective transmission of energy while the medium which is the water through which the wave propagates, move back and forth within a small region
Explanation:
A mechanical wave like other waves is the oscillation of a field about an equilibrium level. In mechanical waves, the field consists of the oscillating matter such that the wave transmits energy through a medium. The displacement of the medium through which the wave energy is limited such that the wave energy is conserved to travel far.
Answer:
a. Wgra=786.09J
b. 1.28m
Explanation:
The change in the potential energy is the work done by the gravitational force.
For this problem you have to take into account that the total work done is given by the change in the kinetic energy
Furthermore the total work is the contribution of the work done by the skater, the gravitational force and the friction
(a) by separating Wfric you have
(b) It is only necessary to use the expression for the work done by gravitational force
HOPE THIS HELPS!!
The distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
<h3>Distance from the center of the meter rule</h3>
The distance from the centre of the rule at which a 2N weight must be suspend from A is calculated as follows;
-----------------------------------------------------------------
20 A (30 - x)↓ x ↓ 20 cm B 30 cm
2N 0.9N
Let the center of the meter rule = 50 cm
take moment about the center;
2(30 - x) + 0.9(x)(30 - x) = 0.9(20)
(30 - x)(2 + 0.9x) = 18
60 + 27x - 2x - 0.9x² = 18
60 + 25x - 0.9x² = 18
0.9x² - 25x - 42 = 0
x = 29.3 cm
Thus, the distance from the centre of the rule at which a 2N weight must be suspend from A is 29.3 cm.
Learn more about brainly.com/question/874205 here:
#SPJ1
