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enyata [817]
3 years ago
12

Name two things in life that require power

Physics
2 answers:
Sever21 [200]3 years ago
7 0
Well it depends on what kind of power you are talking about. With ruling power it could be a president , or teacher.  With electricity power it could be lights , or music.  <span />
Kruka [31]3 years ago
6 0
Lights And Ceiling fan
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Suppose you are testing the buoyancy of different objects. Study the table and choose the object with the greatest buoyant force
Butoxors [25]
According to Archimedes Principle, Buoyant Force is equivalent to the displaced<span> amount of </span><span>fluid, So, Larger the amount of water displaced, more the Buoyant force will be.

In short, Object 3 would have the largest Buoyant Force

Hope this helps!</span>
7 0
3 years ago
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Which are different ways ultrasound technology may be used? Check all that apply.
Kamila [148]

Answer:

Detecting kidney stones and cancer, visualizing fetus in the womb

Explanation:

Ultrasound technology can be used in detecting kidney stones and cancer throat and also visualizing a fetus in the womb. The use of ultrasound for detecting kidney stones started around 1961. Ultrasound has also been used in detecting various types of cancer including throat cancer. The use of ultrasound in knowing the gender of fetus in hospitals has been used for a long time. However, it's not used for cleaning dirty surgical tools.  therefore, choice A, D and E apply.

  • Detecting kidney stones
  • Detecting throat cancer
  • Visualizing a fetus in the womb

8 0
3 years ago
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The moving charge in the wire causes the compass to deflect; this is because
JulijaS [17]

The answer is A. the moving charge induces a magnet field .


5 0
3 years ago
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A constant current is sent through a helical coil. the coil
marissa [1.9K]

Answer:

A. Tends to get shorter.

Explanation:

When a constant current is sent through a helical coil, then currents are different turns will be equal as well as in the same direction. As currents in same direction attract each other, hence coil tends to get shorter.

5 0
3 years ago
A stone is dropped into a river from a bridge at a height h above the water. Another stone is thrown vertically down at a time t
Mumz [18]

Answer:

v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

Explanation:

We will apply the equations of kinematics to both stones separately.

First stone:

Let us denote the time spent after the second stone is thrown as 'T'.

y - y_0 = v_{y_0}(t+T) + \frac{1}{2}a(t+T)^2\\0 - h = 0 + \frac{1}{2}(-g)(t+T)^2\\(t+T)^2 = \frac{2h}{g}\\T = \sqrt{\frac{2h}{g}}-t

Second stone:

y - y_0 = v_{y_0}T + \frac{1}{2}aT^2\\0 - h = v_{y_0}T -\frac{1}{2}gT^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\sqrt{\frac{2h}{g}} - t)^2\\-h = v_{y_0}(\sqrt{\frac{2h}{g}} - t) - \frac{g}{2}(\frac{2h}{g} + t^2 - 2t\sqrt{\frac{2h}{g}})\\-h = v_{y_0}\sqrt{\frac{2h}{g}} - v_{y_0}t - h -\frac{g}{2}t^2 + gt\sqrt{\frac{2h}{g}}\\v_{y_0}(\sqrt{\frac{2h}{g}} - t) = \frac{g}{2}t^2 - gt\sqrt{\frac{2h}{g}}\\v_{y_0} = \frac{\frac{g}{2}t(t - 2\sqrt{\frac{2h}{g}})}{\sqrt{\frac{2h}{g}} - t}

6 0
3 years ago
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