1answer.
Ask question
Login Signup
Ask question
All categories
  • English
  • Mathematics
  • Social Studies
  • Business
  • History
  • Health
  • Geography
  • Biology
  • Physics
  • Chemistry
  • Computers and Technology
  • Arts
  • World Languages
  • Spanish
  • French
  • German
  • Advanced Placement (AP)
  • SAT
  • Medicine
  • Law
  • Engineering
irina1246 [14]
2 years ago
12

When two pumps are used, they can fill a tank in 60 minutes. When the first pump is used alone, the tank will be filled in 150 m

inutes. When x represents the time it takes the second pump to fill the tank when used alone, the situation is represented by this equation: 15 += How long would it take the second pump, working alone, to fill the tank? . OA 75 minutes B. 90 minutes Ос. 100 minutes OD 120 minutes​
Mathematics
1 answer:
EastWind [94]2 years ago
5 0

Using the together rate, it is found that the time it would take the second pump, working alone, to fill the tank is:

B. 90 minutes

The <em>together rate</em> is the <u>sum of each separate rate</u>.

In this problem:

  • The together rate is of 1/60.
  • The first rate is of 1/150.
  • The second rate is of 1/x.

Then:

\frac{1}{150} + \frac{1}{x} = \frac{1}{60}

\frac{x + 150}{150x} = \frac{1}{60}

Applying cross multiplication:

150x = 50x + 9000

100x = 9000

x = \frac{9000}{100}

x = 90

Hence, it would take 90 minutes for the second pump, working alone, to fill the tank.

A similar problem is given at brainly.com/question/25159431

You might be interested in
Need help will give you the brainliest
almond37 [142]

Answer:

147?

Step-by-step explanation:

8 0
3 years ago
Jasmine bought 3500g of flour. She used 3/7 of it to bake some tarts and 700g of it to bake a cake. Find the ratio of the amount
Serggg [28]

Answer: 15:13

Step-by-step explanation: 7/7=3500

<h2>1/7=3500÷7=500</h2><h2>500x3=1500</h2><h2>1500+700=2200</h2><h2>3500-2200=1300</h2><h2>1500:1300</h2><h2>15     :   13 (if there is a need to simplify the                         ratio)</h2><h2 />

6 0
3 years ago
Are the corresponding sides of similar hexagons are always congruent
Lerok [7]
Two polygons are similar if their corresponding angles are congruent and their sides are in proportion.

The sides could be in a ration of 1:1 in which case the two hexagons have corresponding sides that are congruent, but they do not have to be. It could be the case that the sides of one are twice the length of the other so the ratio is 2:1. In this case the hexagons have the same shape but not the same size.

So the answer is this, the corresponding sides of similar hexagons may be congruent but do not have to be.
7 0
3 years ago
Evaluate the expression.<br> 31÷1
natali 33 [55]

Answer:

Step-by-step explanation:

31 is the answer

7 0
2 years ago
Read 2 more answers
Simon opened a certificate of deposit with the money from his bonus check. The bank offered 4.5% interest for 3 years of deposit
iogann1982 [59]

Answer:

$650

Step-by-step explanation:

The for simple interest is

 I = Prt     Divide each side by rt

P = I/(rt)

  = 87.75/(0.045 × 3)

  = $650

Simon deposited $650 to open the account.

6 0
3 years ago
Other questions:
  • 7 less than a number<br><br> A 7-x<br> B 7x<br> C 7 divided x<br> D x-7
    12·1 answer
  • <img src="https://tex.z-dn.net/?f=%20%5Cint%5Climits%20%7B3%20%5E%7B%20%5Cfrac%7Bx%7D%7B2%7D%20%7D%20%7D%20%5C%2C%20dx%20" id="T
    9·2 answers
  • Write an equation for the following tile pattern.<br><br> Figure 2<br><br> Figure 3<br><br> Figure 4
    7·1 answer
  • The total cost to rent 3 chairs and 2 tables is $17 . The total cost to rent 8 chairs and 4 tables is $37 . What is the cost to
    9·2 answers
  • 10 ft area of base 62ft 2 (squared)
    13·1 answer
  • Need help im struggling​
    7·1 answer
  • 6.Calcular: 2^3 ; (-2)^3; ; -2^3 *
    8·1 answer
  • Sorry for my bad handwriting ​
    9·2 answers
  • Endpoint: (6.-2), midpoint: (-1,2)
    11·1 answer
  • On a coordinate plane, what is the distance between the points (-1,5) and (2,5)? Enter the answer in the box.
    10·1 answer
Add answer
Login
Not registered? Fast signup
Signup
Login Signup
Ask question!