Which choices are equations for the line shown below? Check all that apply.

Last year the backgammon club had 30 members this year the club has 24 members find the percent of decrease of members

olchik [2.2K]

Answer:

Percent Decrease = 20% Decrease

Step-by-step explanation:

To find percentage decrease, we will use a simple formula shown below:

Percentage Decrease/Increase = $\frac{New-Old}{Old}*100$

Where

New is the latest number of members (which is 24)

Old is the initial number of members (which is 30)

Note: the multiplication by a factor of "100" brings the answer to a percentage.

Now, lets substitute the numbers and figure out the percentage decrease:

$\frac{New-Old}{Old}*100\\\frac{24-30}{30}*100\\\frac{-6}{30}*100\\-0.2*100\\-20$

So, it comes to -20, which is a decrease of 20%

7 0

3 years ago

A national grocery store chain wants to test the difference in the average weight of turkeys sold in Detroit and the average wei

Arte-miy333 [17]

Answer:

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

The null hypothesis is accepted .

Assume the population variances are approximately the same

Step-by-step explanation:

Explanation:-

Given data a random sample of 20 turkeys sold at the chain's stores in Detroit yielded a sample mean of 17.53 pounds, with a sample standard deviation of 3.2 pounds

The first sample size 'n₁'= 20

mean of the first sample 'x₁⁻'= 17.53 pounds

standard deviation of first sample S₁ = 3.2 pounds

Given data a random sample of 24 turkeys sold at the chain's stores in Charlotte yielded a sample mean of 14.89 pounds, with a sample standard deviation of 2.7 pounds

The second sample size n₂ = 24

mean of the second sample "x₂⁻"= 14.89 pounds

standard deviation of second sample S₂ = 2.7 pounds

Null hypothesis:-H₀: The Population Variance are approximately same

Alternatively hypothesis: H₁:The Population Variance are approximately same

Level of significance ∝ =0.05

Degrees of freedom ν = n₁ +n₂ -2 =20+24-2 = 42

Test statistic :-

$t = \frac{x^{-} _{1} - x_{2} }{\sqrt{S^2(\frac{1}{n_{1} } }+\frac{1}{n_{2} } }$

where $S^{2} = \frac{n_{1} S_{1} ^{2}+n_{2}S_{2} ^{2} }{n_{1} +n_{2} -2}$

$S^{2} = \frac{20X(3.2)^2+24X(2.7)^2}{20+24-2}$

substitute values and we get S² = 40.988

$t= \frac{17.53-14.89 }{\sqrt{40.988(\frac{1}{20} }+\frac{1}{24} )}$

t = 1.3622

Calculated value t = 1.3622

Tabulated value 't' = 2.081

Calculated value t = 1.3622 < 2.081 at 0.05 level of significance with 42 degrees of freedom

Conclusion:-

The null hypothesis is accepted

Assume the population variances are approximately the same.

6 0

3 years ago

Which of the following numbers are greater than or equal to 4/7

Alexandra [31]

B and C mark brainly!

8 0

3 years ago

What is 56.398 rounded to the nearest tenth?

Vesna [10]

Well when you round to the nearest 10 it will be 1 number after the point (this is due to that 10 only has one 0.) now we know that if there is a number bigger than 5 besides the number they ask you in this case the first after the point you will add 1 to that number. in this case you will add 1 to the 3. this will give you the answer of 56.4

Hope this helps

6 0

3 years ago

Which statement is true about the value of 1-512

Anestetic [448]

Answer:

It is the distance that -5 is from 0 on the number line

Step-by-step explanation:

I learned this last month

Hope this helps

4 0

3 years ago

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