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2 years ago

Hi, I was wondering about this one. Its multi step

Mathematics

1 answer:

Nana76 [90]2 years ago

4 0

Answer:

12 are having pie, 12 are not having pie.

Step-by-step explanation:

We can find out how many of Jayla's friends want a slice of pie by taking the total amount of her friends (23) and subtracting the amount who do not want pie. The equation is:

23 - 12 = 11

Because Jayla wants a slice too, we will add 1 to the 11 friends who want a slice. The equation is:

11 + 1 = 12

So 12 people are having pie, while 12 are not.

BONUS: The gluten free friends may have pie too because I remembered them and I baked the crust so that it is gluten free.

Hope this helps friend.

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What is the answer for 3a

n200080 [17]

24/40 = T/30
40t= 24•(30)
T= 18
Hope this helps. :)

8 0

3 years ago

Solve 5h + 2(11 - h) = -5 (Find h. Explain each step please.)

pav-90 [236]

Answer:

h = -9

Step-by-step explanation:

Distribute the 2 to the parentheses:

5h + 2(11 - h) = -5

5h + 22 - 2h = -5

Add like terms:

3h + 22 = -5

3h = -27

h = -9

7 0

3 years ago

Read 2 more answers

Which set of measurements could represent the three sides of a triangle?

yawa3891 [41]

Answer:

The side lengths of a right triangle is 11cm, 60cm and 61cm, that could be selected from the given measurements.

Step-by-step explanation:

The measurements are,

7cm, 11cm, 54cm, 60cm, 61cm, 65cm

Step:1

To check the right angle triangle, Pythagorean theorem can be used.

For a Pythagorean theorem,

..........................(1)

The side values are lower than the hypotenuse,

...................................(2)

Where,

a,b - side values

c - Hypotenuse

For right angle triangle, c > a, b

Alternative : 1

Take, a = 7cm, b = 11cm

From eqn (2),

= = 13.04

The above value is not equal to the any one of the values of ( 54cm. 60cm, 61cm, 65cm ), So its not an sides of right triangle.

Alternative : 2

Take, a = 7cm, b = 54cm

From eqn (2),

= = 54.45

The above value is not equal to the any one of the values of (60cm, 61cm, 65cm ), So its not an sides of right triangle.

Alternative : 3

Take, a = 7cm, b = 60cm

From eqn (2),

= = 60.406

The above value is not equal to the any one of the values of (61cm, 65cm ), So its not an sides of right triangle.

Alternative : 4

Take, a = 7cm, b = 61cm

From eqn (2),

= = 61.40

The above value is not equal to the values of (65cm ), So its not an sides of right triangle.

Alternative : 5

Take, a = 11cm, b = 54cm

From eqn (2),

= = 55.1089

The above value is not equal to the any one of the values of (60cm, 61cm, 65cm ), So its not an sides of right triangle.

Alternative : 6

Take, a = 11cm, b = 60cm

From eqn (2),

= = 61

The above value is equal to the values of (61cm ), So its an sides of right triangle. The three sides are 11, 60 and 61.

Step:2

Check for solution,

Result:

The side lengths of a right triangle is 11cm, 60cm and 61cm, that could be selected from the given measurements.

Step-by-step explanation: The side lengths of a right triangle is 11cm, 60cm and 61cm.

4 0

3 years ago

Find the roots of:

Elena-2011 [213]

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{1) \ 2x^3-7x^2+8x-3=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -3 are 1, -1, 3, +3. So:

| 2 -7 8 -3

1 | 2 -5 3

| 2 -5 3 0

1 | 2 -3

2 -3 0

So the factorization is (x-1)² (2x-3)=0. So:

$\bf{ x_1=x_2=1 \qquad x_2=\dfrac{3}{2} }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{2) \ x^3-x^2-4=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of -4 are 1, -1, 2, -2, 4, -4. So:

| 1 -1 0 -4

2 | 2 2

1 2 2 0

So the factorization is (x-2)(x²+x+2)=0 . When calculating the discriminant of the trinomial, it is concluded that it has no roots since the result is negative. So you only have one solution.

$\bf{ 1^2-4(2)(2)=1-16=-15 < 0 \quad \Longrightarrow \quad x=2 }$

$\large\displaystyle\text{$\begin{gathered}\sf \pmb{3) \ 6x^3+7x^2-9x+2=0 } \end{gathered}$}$

Synthetic division is used since the equation is of the third degree. The divisors of 2 are 1, -1, 2, -2. So:

| 6 7 9 2

-2 | -12 10 -2

6 -5 1 0

So the factorization is (x+2)(6x²-5x+1)=0 . The quadratic equation is solved by the general formula:

$\bf{ x_{2, 3}&=\dfrac{5\pm \sqrt{(5)^2-4(6)(1)}}{2(6)}=\dfrac{5\pm \sqrt{25-24}}{12}=\dfrac{5\pm 1}{12} }}$

$\large\displaystyle\text{$\begin{gathered}\sf \begin{matrix} x_1=-2&\ \ \ \ \ \ x_{2}=\dfrac{6}{12} \qquad &\ \ \ x_3=\dfrac{4}{12}\\ &\ \ \ x_2=\dfrac{1}{2} \qquad &x_3=\dfrac{1}{3} \end{matrix} \end{gathered}$}$

6 0

2 years ago

I need help on 9 11 14 and 16

TEA [102]

Answer:

For 9 the answer is (4)

For 11 the answer is (5)

For 14 the answer is (4)

I cant see number 16 so maybe retake the photo thanks!

Step-by-step explanation:

9. squares have two sets of parallel lines

11. The only quadrilateral that has 3 different side lengths on this list is a trapezoid

14. It has no right angles meaning its not a square or rectangle. It has two sets of parallel sides meaning its not a trapezoid, and since it gives two different side lengths its not a rhombus since all sides muse be congruent to be a rhombus. The only one that matches is 4 a parallelogram

7 0

3 years ago