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____ [38]
3 years ago
7

What region of the spectrum best corresponds to light with a wavelength equal to.

SAT
1 answer:
KonstantinChe [14]3 years ago
5 0

The region of the spectrum that best corresponds to light with a wavelength equal to;

1) The diameter of a hydrogen atom is; X-ray

2) The width of your pinky finger; microwaves.

3) The size of a virus; X-ray and Ultraviolet rays.

<h3>Electromagnetic spectrum</h3>
  • From online tables, the diameter of an hydrogen atom is approximately 1 × 10^(-10) m but according to electromagnetic spectrum, any wavelength between 10^(-8) m and 10^(-12) m is an x-ray.

  • From online tables, width of your pinky finger is 1.06 × 10^(-2) m but according to the electromagnetic spectrum the range between 1 and 10^(-3) m corresponds to microwave.

  • The size of a virus has the range from 2 × 10^(-9) m to 4 × 10^(-7) m. This Range falls into x-ray or ultraviolet rays.

The complete question is;

What region of the spectrum best corresponds to light with a wavelength equal to:

(1) the diameter of a hydrogen atom

(2) the width of your pinky finger

(3) the size of a virus

Choices:

(A) radio

(B) mircowave

(C) infrared

(D) visible light

(E) gamma ray

(F) x-ray

(G) ultraviolet

Read more about Wavelength at; brainly.com/question/24790737

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What values of c and d would make the following expression represent a real number? i(2 3i)(c di) c = 2, d = 3 c = –2, d = 3 c =
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Complete question:

<em>What values of c and d would make the following expression represent a real number? i(2 + 3i)(c + di) </em>

<em>choices: A)c = 2, d = 3 B)c = –2, d = 3 C)c = 3, d = –2 D)c = –3, d = –2</em>

<em />

<em>Option D</em><em> is correct. </em> The value of c and d for the expression to be real are -3 and -2 respectively

Given the expression

i(2 + 3i)(c + di)

Expand the expression

=i(2 + 3i)(c + di)\\=(2i+3i^2)(c+di)\\=(2i+3(-1))(c+di)\\=(2i-3)(c+di)\\=2ic+2di^2-3c-3di\\=2ic-2d-3c-3di

Collect the like terms

=2ic-3di-2d-3c

For the resulting function to be real, then the imaginary part must be zero i.e.

2ic-3di=0\\2ci = 3di\\2c = 3d\\c=\frac{3d}{2}\\

If d = -2, then;

c=\frac{3(-2)}{2}\\c=\frac{-6}{2}\\c= -3

Hence the value of c and d for the expression to be real are -3 and -2 respectively.

Learn more here: brainly.com/question/4244460

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