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2 years ago

I ASKED THIS QUESTION OVER 20 TIMES PLEASE HELP

Chemistry

2 answers:

noname [10]2 years ago

8 0

Answer:

230 grams

Explanation:

ivolga24 [154]2 years ago

8 0

Answer:

230 grams

Explanation:

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A certain half-reaction has a standard reduction potential E0red = +0.13V . An engineer proposes using this half-reaction at the

Ivan

Answer:

a. 1.23 V

b. No maximum

Explanation:

Required:

a. Is there a minimum standard reduction potential that the half-reaction used at the cathode of this cell can have?

b. Is there a maximum standard reduction potential that the half-reaction used at the cathode of this cell can have?

The standard cell potential (E°cell) is the difference between the standard reduction potential of the cathode and the standard reduction potential of the anode.

E°cell = E°red, cat - E°red, an

If E°cell must be at least 1.10 V (E°cell > 1.10 V),

E°red, cat - E°red, an > 1.10 V

E°red, cat - 0.13V > 1.10 V

E°red, cat > 1.23 V

The minimum standard reduction potential is 1.23 V while there is no maximum standard reduction potential.

4 0

3 years ago

In the presence of excess oxygen, methane gas burns in a constant-pressure system to yield carbon dioxide and water: CH4 (g) 2O2

Degger [83]

Answer:

The energy released will be -94.56 kJ or -94.6 kJ.

Explanation:

The molar mass of methane is 16g/mol

The given reaction is:

$CH_{4}(g) + 2O_{2} (g) --> CO_{2} (g)+ 2H_{2}O(l)$

the enthalpy of reaction is given as ΔH = -890.0 kJ

This means that when one mole of methane undergoes combustion it gives this much of energy.

Now as given that the amount of methane combusted = 1.70g

The energy released will be:

$=\frac{energy released by one moleXgiven mass}{molarmass} =\frac{-890X1.7}{16}= -94.56 kJ$

7 0

2 years ago

One mole of carbon (12.0 g) in the form of crystalline graphite is burned at 25◦C and 1.000 atm pressure to form CO2(g). All of

iogann1982 [59]

Answer:

T₂ = 43.46 °C

Explanation:

Given that:

The heat of the formation of carbon dioxide = - 393.5 kJ/mol (Negative sign suggests heat loss)

It means that energy released when 1 mole of carbon undergoes combustion = 393.5 kJ = 393500 J

Heat gain by water = Heat lost by the reaction

Thus,

$m_{water}\times C_{water}\times \Delta T=Q$

For water:

Mass of water = 5100 g

Specific heat of water = 4.18 J/g°C

T₁ = 25 °C

T₂ = ?

Q = 393500 J

So,

$5100\times 4.18\times (T_2-25)=393500$

T₂ = 43.46 °C

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2 years ago

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dimulka [17.4K]

Why you saying we can download an answer we’re here for an answer

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2 years ago