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Goshia [24]
3 years ago
14

What evidence from the experiment shows that conduction occurred? In your answer, be sure to include the materials involved in t

he transfer of heat through conduction.
Chemistry
2 answers:
velikii [3]3 years ago
5 0

Answer:

Explanation:

The melting of the chocolate pieces one by one showed that it was caused by heat flowing through the foil bridge. The transfer of heat happened between the foil bridge and the chocolate pieces because they were touching each other.

tamaranim1 [39]3 years ago
3 0

Answer: check explanation

Explanation:

Heat transfer is the exchange of thermal energy between physical system. Heat can be transferred through conduction, convection and radiation.

The transfer of energy in the form of heat from one atom to another is known as CONDUCTION.

The movement of molecules within fluids is known as CONVECTION.

The electromagnetic radiation produced by the motion of particles in matter is known as THERMAL RADIATION.

The EXPERIMENT INVOLVE THE MELTING OF CHOCOLATE. At a certain temperature the chocolate pieces for the experiment undergo a physical change, from a solid to a liquid. Since the pieces of Chocolate and the foil bridge are touching each other, Heat is transferred between the chocolate pieces and foil bridge.

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Someone help please I don’t know the answer to the question I meeed help
mihalych1998 [28]

Answer: 143.3  

137+115+104+263+98 divided by 5.Which gives us 143.3

5 0
3 years ago
If you were to travel from the surface to the center of Earth, the temperature would
nataly862011 [7]

Answer:

increase dramatically(a lot).

Explanation:

The core of the earth is way way way hotter than the surface.

5 0
3 years ago
Estimate the standard internal energy of formation of liquid methyl acetate (methyl ethanoate, ch3cooch3) at 298 k from its stan
LenKa [72]

solution:

the reaction for formation of methyl acetate is\\CH_{3}OH+CH_{3}COOH----------->CH_{3}COOCH_{3}+H_{2}O\\standard internal energy \\\delta u=\delta H -\delta(pv)=\delta H -\delta n\times RT\\where \delta n=change in number of moles=0\\\delta u=\delta H\\=-442kj/mol

6 0
3 years ago
Read 2 more answers
Please help<br> Explain why a molecule that has polar bonds can be a polar molecule.
Zepler [3.9K]

Answer:

Explanation:

Well, obviously a molecule with polar bonds can be polar in itself. It's like saying I am an atheltic person who can just reach the basketball rim with my head and also I can dunk.

But if the question is how can a molecule that in non-polar have polar bonds, well, its because the polar bonds' dipole cancels each other out. It's like a tight rope. If a person pulls in one direction, it intuitively, the rope would go in that direction. However, if a person pulls in the other direction with the same amount of force, the rope stays still. This is the same case. Although molecules can have different electronegativities, the pull of electrons in one direction is cancelled out by a pull in the opposite direction, making the net dipole 0.

This is common for main VSERP shaped molecules like linear, trigonal planar, tetrahedral, trigonal bipyramidal, and octahedral.

8 0
3 years ago
Since helium is lighter than air, it is difficult to measure the mass of a sample, so to find out the mass of helium in a birthd
d1i1m1o1n [39]

Answer:

0.7457 g is the mass of the helium gas.

Explanation:

Given:  

Pressure = 3.04 atm

Temperature = 25.0 °C

The conversion of T( °C) to T(K) is shown below:

T(K) = T( °C) + 273.15  

So,  

T₁ = (25.0 + 273.15) K = 298.15 K  

Volume = 1.50 L

Using ideal gas equation as:

PV=nRT

where,  

P is the pressure

V is the volume

n is the number of moles

T is the temperature  

R is Gas constant having value = 0.0821 L.atm/K.mol

Applying the equation as:

3.04 atm × 1.50 L = n × 0.0821 L.atm/K.mol × 298.15 K  

<u>⇒n = 0.1863 moles</u>

Molar mass of helium = 4.0026 g/mol

The formula for the calculation of moles is shown below:

moles = \frac{Mass\ taken}{Molar\ mass}

Thus,

0.1863\ mole= \frac{Mass}{4.0026\ g/mol}

Mass_{He}= 0.7457\ g

<u>0.7457 g is the mass of the helium gas. </u>

6 0
3 years ago
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