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3 years ago

Why is the voltage of the supply decreased before entering our homes ?

Physics

1 answer:

Reptile [31]3 years ago

3 0

Answer:

After power is generated at a power plant, its voltage is increased by a step-up transformer. The power then travels through transmission lines to a neighborhood where it will run homes, offices, and factories. But before entering the neighborhood, the power's voltage is decreased by a step-down transformer

Transformers can be used either to increase the voltage (called "stepping up") or decrease the voltage ("step down"). When electrical energy travels long distances in wires, some of the energy is lost. ... Later, the voltage is stepped down before it enters your home - once again using transformers

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Please Help with this

Tresset [83]

Answer: c is correct

Explanation: i did this

3 0

3 years ago

A helicopter has blades of length 4.0 m rotating at 3.0 rev/s in a horizontal plane.If the vertical component of the Earth’s mag

VARVARA [1.3K]

Answer:

Induced emf, $\epsilon=9.79\times 10^7\ volts$

Explanation:

Given that,

Length of the helicopter, l = 4 m

Angular speed of the helicopter, $\omega=3\ rev/s=18.84\ rad/s$

The vertical component of the Earth’s magnetic field is, $B=6.5\times 10^5\ T$

We need to find the induced emf between the tip of a blade and the hub. The induced emf in terms of angular velocity of an rotating object is given by :

$\epsilon=\dfrac{1}{2}B\omega l^2$

$\epsilon=\dfrac{1}{2}\times 6.5\times 10^5\times 18.84\times (4)^2$

$\epsilon=9.79\times 10^7\ volts$

So, the induced emf between the tip of a blade and the hub is $\epsilon=9.79\times 10^7\ volts$ . Hence, this is the required solution.

5 0

3 years ago

A dad takes his kids to their school just 8.0 miles down the road but with traffic it takes him 30 minutes and the fastest he ca

VARVARA [1.3K]

Answer:C 24 mi/hr

Explanation:

8 0

3 years ago

A 850-kg sports car accelerates from rest to 95 km/h in 6.8 s .

swat32

From the calculations, the power expended is 43650 W.

<h3>What is the power expended?</h3>

Now we can find the acceleration from;

v = u + at

u = 0 m/s

v = 95 km/h or 26.4 m/s

t = 6.8 s

a = ?

Now

v = at

a = v/t

a = 26.4 m/s/ 6.8 s

a = 3.88 m/s^2

Force = ma = 850-kg * 3.88 m/s^2 = 3298 N

The distance covered is obtained from;

v^2 = u^2 + 2as

v^2 = 2as

s = v^2/2a

s = (26.4)^2/2 * 3.88

s = 696.96/7.76

s = 90 m

Now;

Work = Fs

Work = 3298 N * 90 m = 296820 J

Power = 296820 J/ 6.8 s

= 43650 W

Learn more about power expended:brainly.com/question/11579192

#SPJ1

5 0

2 years ago

Consider the 65 N light fixture supported as in the figure. Find the tension in the supporting wires.

ASHA 777 [7]

By using Lami's theorem formula, the tension in the supporting wires is 48.6 Newtons

TENSION

Tension is also a force having Newton as S.I unit.

The tension in the wire will be the same.

This question can be solved by using either vector diagram or by using Lami's theorem.

The sum of two given angles = 42 + 42 = 84 degrees

The third angle = 180 - 84 = 96 degrees.

Below is the Lami's theorem formula

$\frac{T}{sin\alpha } = \frac{T}{sin\beta } = \frac{W}{sinY}$

Where

$\alpha = \beta$ = 42 + 90 = 132 degrees

Y = 96 degrees

W = 65 N

By using the formula, we have

$\frac{T}{sin\alpha } = \frac{W}{sinY}$

T/sin 132 = 65/sin96

Cross multiply

T = 0.743 x 65.57

T = 48.56 N

Therefore, the tension in the supporting wires is 48.6 Newtons approximately.

Learn more about Tension here: brainly.com/question/24994188

3 0

3 years ago